Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 78)
78.
What will be remainder when 17200 is divided by 18 ?
Answer: Option
Explanation:
When n is even. (xn - an) is completely divisibly by (x + a)
(17200 - 1200) is completely divisible by (17 + 1), i.e., 18.
(17200 - 1) is completely divisible by 18.
On dividing 17200 by 18, we get 1 as remainder.
Discussion:
27 comments Page 2 of 3.
Hamsa said:
6 years ago
What is the remainder when 79^59 is divided by 40.
Gopi said:
7 years ago
17^200 - 1 = 18 * quotient.
So,
17^200 = 18 * quotient + 1.
We have taken that 1 as a reminder in all type of problems.
So, ans = 1.
So,
17^200 = 18 * quotient + 1.
We have taken that 1 as a reminder in all type of problems.
So, ans = 1.
Rounak said:
7 years ago
What to do when n is odd number?
Manoranjan sahoo said:
7 years ago
(17^199+17)/18,
(17^199+1)/18 is completely divisible,
and the reminder is 16.
(17^199+1)/18 is completely divisible,
and the reminder is 16.
Akhil said:
1 decade ago
Why cant it be (17^200-2^200) is completely divisible by 17+2=19 ?
Shubham said:
8 years ago
Can somebody give all the division rules for term (x^n - a^n).
ESRAK AHMED KAFI said:
9 years ago
x^n -1 is divisible by (X+1) when n is even. so, when we will divide X^n by (X+1) the remainder will be definitely 1.
Example: 2^2 =4, when 4 is divided by (2+1) i.e. 3, then the remainder will be 1.
Example: 2^2 =4, when 4 is divided by (2+1) i.e. 3, then the remainder will be 1.
Sweety said:
9 years ago
Please, anyone explain this clearly.
Dev said:
9 years ago
Please give me solution for finding the value of R. And explain the answer.
26^57÷29 = R.
128^100÷153 = R.
2^187÷51 = R.
17^14÷72 = R.
26^57÷29 = R.
128^100÷153 = R.
2^187÷51 = R.
17^14÷72 = R.
Mir Rokon Uddin said:
9 years ago
It is notable that the power of 17 is even.
So we can consider 17^2 and divide it by 18. And we got 1 as a reminder. So the answer is 1.
So we can consider 17^2 and divide it by 18. And we got 1 as a reminder. So the answer is 1.
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