Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 14)
14.
If logx y = 100 and log2 x = 10, then the value of y is:
Answer: Option
Explanation:
log 2 x = 10 
x = 210.
logx y = 100
y = x100
y = (210)100 [put value of x]
y = 21000.
Discussion:
6 comments Page 1 of 1.
Satish said:
1 decade ago
log2x = 10 can be written as logx2= 1/10.
So we have,
logxy = 100 and logx2= 1/10.
Now lets divide them,
logxy / logx2= 100/10 = 10.
So the result would be log2y = 10.
Which gives us why = 2 10.
This is what I got as an answer! please correct me where I'm going wrong! : (.
So we have,
logxy = 100 and logx2= 1/10.
Now lets divide them,
logxy / logx2= 100/10 = 10.
So the result would be log2y = 10.
Which gives us why = 2 10.
This is what I got as an answer! please correct me where I'm going wrong! : (.
Felix said:
1 decade ago
@Serif.
The error you have made is that instead of dividing by 1/10 you have just divided by. Otherwise the Method you followed is correct.
The error you have made is that instead of dividing by 1/10 you have just divided by. Otherwise the Method you followed is correct.
Preethi said:
1 decade ago
Please explain me I did not understand.
Deepanesh said:
5 years ago
Anyone Solve this by using the formula.
G mahendra Kumar said:
4 years ago
Good, Thanks for solving @Satish.
Alok Paramanik said:
4 years ago
@Satish.
Logxy = 100 and logx2= 1/10.
Now lets divide them,
Logxy / logx2= 100/ (1/10) = 1000.
So the result would be log2y = 1000.
This gives us y = 2^1000.
Logxy = 100 and logx2= 1/10.
Now lets divide them,
Logxy / logx2= 100/ (1/10) = 1000.
So the result would be log2y = 1000.
This gives us y = 2^1000.
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