Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 3)
3.
The angle of elevation of a ladder leaning against a wall is 60° and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is:
Answer: Option
Explanation:
Let AB be the wall and BC be the ladder.
Then, 
ACB = 60° and AC = 4.6 m.
| AC | = cos 60° = | 1 |
| BC | 2 |
 BC |
= 2 x AC |
| = (2 x 4.6) m | |
| = 9.2 m. |
Discussion:
45 comments Page 5 of 5.
Priya said:
8 years ago
Because of cos = adjacent/hypotenuse if we take tan it becomes AB/AC we need a length of the ladder ie BC so we take cos, ie AC/BC.
Shyam said:
1 decade ago
Why the above two problem we taking "tan", but for this problem we took "cos". Anyone explain ?
Gaurav said:
7 years ago
@Nikita.
How these combinations of base and perpendicular, hypotenuse and perpendicular, hypotenuse and base and so on are formed?
Just tell where is the rule that cos will be equal to Base/Perpendicular rather than Base/Hypotenuse?
How these combinations of base and perpendicular, hypotenuse and perpendicular, hypotenuse and base and so on are formed?
Just tell where is the rule that cos will be equal to Base/Perpendicular rather than Base/Hypotenuse?
Puneet kulkarni said:
7 years ago
We have formula:
Tan=perpendicular/base
Sine=perpendicular/hypothesis
Cos=base/hypothesis.
Tan=perpendicular/base
Sine=perpendicular/hypothesis
Cos=base/hypothesis.
Neeraj said:
7 years ago
Why can't we solve this using tan?
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