Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 3)
3.
The angle of elevation of a ladder leaning against a wall is 60° and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is:
Answer: Option
Explanation:
Let AB be the wall and BC be the ladder.
Then, ACB = 60° and AC = 4.6 m.
AC | = cos 60° = | 1 |
BC | 2 |
![]() |
= 2 x AC |
= (2 x 4.6) m | |
= 9.2 m. |
Discussion:
45 comments Page 4 of 5.
GAGAN said:
4 years ago
@Anil Kumar.
But they have asked BC not AB. Why are you finding AB?
But they have asked BC not AB. Why are you finding AB?
(1)
Altamash Bagwan said:
6 years ago
In this question, cos indicate is an adjacent side/hypotenuse side.
JIT said:
8 years ago
If we take,
tan30=AC/BC,
BC=7.8.
Why can't we solve in this way?
tan30=AC/BC,
BC=7.8.
Why can't we solve in this way?
(1)
Anant said:
1 decade ago
tan60 = x/4.6.
x = tan60*4.6.
x = 1.732*4.6.
Therefore, x = 7.8.
x = tan60*4.6.
x = 1.732*4.6.
Therefore, x = 7.8.
Brinda said:
6 years ago
@Chiru.
Yes, you are right and when Tan is taken answer is 7.9.
Yes, you are right and when Tan is taken answer is 7.9.
Fgrg said:
1 decade ago
Can't we do this with the 30, 60, 90 triangle method?
Deepali said:
4 years ago
why we take cos here? Explain please.
(1)
Rajan said:
9 years ago
Why can't we use sec instead of cos?
(1)
Neeraj said:
7 years ago
Why can't we solve this using tan?
Praveen kumar said:
9 years ago
Great answer Thanks @Rahul Rami.
(1)
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