Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 5)
5.
From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:
Answer: Option
Explanation:
Let AB be the tower.
Then, 
APB = 30° and AB = 100 m.
| AB | = tan 30° = | 1 |
| AP | 3 |
 AP |
= (AB x 3) m |
| = 1003 m | |
| = (100 x 1.73) m | |
| = 173 m. |
Discussion:
29 comments Page 3 of 3.
Mounika said:
5 years ago
Why tan only? Please explain.
Vikas said:
5 years ago
Why tan only?
Because we find the height of the tower that we get tan30 because;
tan30 = perpendicular/base.
Because we find the height of the tower that we get tan30 because;
tan30 = perpendicular/base.
(1)
Rutuja said:
4 years ago
how Root 3 is calculated as 1.73?
Please anyone explain it.
Please anyone explain it.
(1)
Vivek Sunny said:
4 years ago
Approach 1*1= 1,
1.5*1.5=2.25,
2*2=4,
so.
√ 3 is between 1.5 and 2 so 1.73 is correct.
1.5*1.5=2.25,
2*2=4,
so.
√ 3 is between 1.5 and 2 so 1.73 is correct.
(3)
Sagar said:
4 years ago
1.73 how?
(2)
Bala murali said:
3 years ago
Here, tan 30 is 1/√3.
Then how will 100/√3 become 1.73?
Then how will 100/√3 become 1.73?
(4)
Shivraj Singh said:
2 years ago
The value of √ 3 is 1.73.
(3)
Deeps said:
2 years ago
Why can't we use sin30?
It is also perpendicular right?
It is also perpendicular right?
(5)
Shivam said:
7 months ago
@All.
The correct approach would be using sin 30 as we are given the value of perpendicular i.e. height of the tower and have to find the value of base distance b/w the tower and point p.
The correct approach would be using sin 30 as we are given the value of perpendicular i.e. height of the tower and have to find the value of base distance b/w the tower and point p.
(1)
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