Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 5)
5.
From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:
Answer: Option
Explanation:
Let AB be the tower.
Then, 
APB = 30° and AB = 100 m.
| AB | = tan 30° = | 1 |
| AP | 3 |
 AP |
= (AB x 3) m |
| = 1003 m | |
| = (100 x 1.73) m | |
| = 173 m. |
Discussion:
29 comments Page 2 of 3.
Sravan said:
8 years ago
100 √3 has given its clear but how to calculate √3 value?
Please explain it.
Please explain it.
Divyanshi shrivastava said:
9 years ago
@Aswin.
We using tan because using the formula of TAN we can solve the solution easily.
We using tan because using the formula of TAN we can solve the solution easily.
Sangeethasendhil said:
8 years ago
If we use sin 30 then answer will be 200, so how can I identify for correctly tan 30?
Ravi said:
8 years ago
Why can we use tan instead using sin or cos? please tell me the solution.
Vaibhav shelar said:
8 years ago
No, according to 30-60-90 theorem rule answer must be 100√(3).
Bala murali said:
3 years ago
Here, tan 30 is 1/√3.
Then how will 100/√3 become 1.73?
Then how will 100/√3 become 1.73?
(4)
Gitanshu said:
6 years ago
How to divide 34.64/1.732 without calc. Is there any simple trick?
(2)
Poorvi said:
9 years ago
But tan30 is 1 by root 3. Then how will 100 by root 3 becomes 173?
Nissipravalika said:
5 years ago
Hi,
How to calculate √3 value?
Anyone can explain please?
How to calculate √3 value?
Anyone can explain please?
(1)
Priya said:
6 years ago
Thank you so much @Sarthak.
You explained it neat and clear.
You explained it neat and clear.
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