Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
63 comments Page 4 of 7.
Vivek Sunny said:
4 years ago
@Aditya.
We can choose any ratio either tan or cot.
But, which relates both adjacent and height.
We can choose any ratio either tan or cot.
But, which relates both adjacent and height.
Hemamalini said:
1 month ago
How is Cot taken? Please explain to me.
Lavanya said:
1 decade ago
Guys they said shadow of the tree is root 3 times of its height that is if we take height as "x" then base is "root 3x".
If we do by using Tan then:
Tan theta = Height/Base.
= x/root 3x.
By cancelling we will get 1/root 3.
Theta = tan-1(1/root 3).
i.e theta = 30 that's it.
If we do by using Tan then:
Tan theta = Height/Base.
= x/root 3x.
By cancelling we will get 1/root 3.
Theta = tan-1(1/root 3).
i.e theta = 30 that's it.
Kapil said:
2 decades ago
Angle ACB = Angle BCA
There are different ways to do same question.
they are using cot @ =AC/BC
but you can also use tan @ = perpendicular/base = AB/AC
There are different ways to do same question.
they are using cot @ =AC/BC
but you can also use tan @ = perpendicular/base = AB/AC
Balaji said:
2 decades ago
Let me explain here, here carefully,
Here in the problem tree is taken as perpendicular i.e. AB and they also informed that the shadow of tree 3 times the tree i.e. 3 AB. Here shadow is nothing but base.
So we have formula that cot thita = cos θ/ sin θ
Cot θ= AC/AB
= 3 * AB/AB
Cot θ= 3
Cot θ= Cot 30
θ = 30
Here in the problem tree is taken as perpendicular i.e. AB and they also informed that the shadow of tree 3 times the tree i.e. 3 AB. Here shadow is nothing but base.
So we have formula that cot thita = cos θ/ sin θ
Cot θ= AC/AB
= 3 * AB/AB
Cot θ= 3
Cot θ= Cot 30
θ = 30
Appu said:
2 decades ago
Thank you Balaji.
Anchal said:
1 decade ago
We can also solve like this...let AB=x, then AC=3x, Now
AB/AC=tanθ
then x/3=tanθ
After crossing x from x..we get
1/3=tanθ
so tan 30=1/3
so θ=30...Ans..
AB/AC=tanθ
then x/3=tanθ
After crossing x from x..we get
1/3=tanθ
so tan 30=1/3
so θ=30...Ans..
Kanaga said:
1 decade ago
Hi,
I am not getting the question correctly. They have asked about the angle of elevation of sun. Why should we go for angle of elevation of tree?
I am not getting the question correctly. They have asked about the angle of elevation of sun. Why should we go for angle of elevation of tree?
Baribie said:
1 decade ago
Can any one explain the question?
Mjp said:
1 decade ago
The sun forms a angle of depression. So as the sun is very far away it is hard to take the value, so we can take the angle of elevation of a tree which is equal to the angle of depression.
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