Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
62 comments Page 3 of 7.
Nitin said:
9 years ago
The question says the heights of the tree is 3 times the shadow of the tree but the correct answer comes only when we take root 3 times?
Manu said:
1 decade ago
Consider the height of the tree is 'x' m. Then the shadow is (3)^1/2. And apply tan or cot based on the relation which you want to find.
Idiotshere said:
1 decade ago
Help me please!.
I'm not getting here why we are saying ACB why don't BCA ?
And another is that why AC/AB why don't AB/AC = tan60 ?
I'm not getting here why we are saying ACB why don't BCA ?
And another is that why AC/AB why don't AB/AC = tan60 ?
(1)
Dattatray said:
7 years ago
Let x be the height of tree and shadow length √3 x,
Tanθ= x &div √3 x.
θ=tan-1(1 &div √3),
θ=30.
Tanθ= x &div √3 x.
θ=tan-1(1 &div √3),
θ=30.
Nicholas Hatontola said:
3 years ago
Why are we considering BC as the length of the shadow instead of AC? Isn't the shadow supposed to be the base?
Please explain me.
Please explain me.
(1)
Ashish kaushik said:
10 years ago
Its simple let AB = x then ac = root3x.
Tan theta = ab/ac = x/root 3x = 1/root3.
Then tan theta =1/root3 = 30 degree.
Tan theta = ab/ac = x/root 3x = 1/root3.
Then tan theta =1/root3 = 30 degree.
Vinay said:
9 years ago
Can anyone explain me taking of angle ACB and why not ABC?
Am thinking the eye of the sun for elevation is from b.
Am thinking the eye of the sun for elevation is from b.
Aadil said:
8 years ago
Angle = Tan inverse of( Opposite side/ Adjacent side).
So, the Final answer is 30 deg. As tan inverse of 1/root3.
So, the Final answer is 30 deg. As tan inverse of 1/root3.
Sai Aswin said:
6 years ago
SHORT CUT:
Shadow=√3(height of the tree).
(Shadow/height of tree)= √3,
So, cotθ = √3=30°.
Shadow=√3(height of the tree).
(Shadow/height of tree)= √3,
So, cotθ = √3=30°.
Kelzhenry said:
7 years ago
AB/AC = Tanθ.
From the question,
AB/√3AB =Tanθ
1/√3 = Tanθ
θ = 30°.
From the question,
AB/√3AB =Tanθ
1/√3 = Tanθ
θ = 30°.
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