Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let ACB =
.
Then, | AC | = | 3 ![]() ![]() |
AB |
= 30°.
Discussion:
62 comments Page 2 of 7.
Mahendra said:
8 years ago
Let height of the shadow = x.
Then the shadow of the is root3 times the height of the tree = root3*x.
Nnow tan θ =x/root3*x.
x,x gets cancel and 1/3 remains.
we know the tan1/3 = 30°.
Then the shadow of the is root3 times the height of the tree = root3*x.
Nnow tan θ =x/root3*x.
x,x gets cancel and 1/3 remains.
we know the tan1/3 = 30°.
Mjp said:
1 decade ago
The sun forms a angle of depression. So as the sun is very far away it is hard to take the value, so we can take the angle of elevation of a tree which is equal to the angle of depression.
Palash said:
9 years ago
I am not getting the question's meaning. They have included two objectives (tree as well as sun) but which one should I take to solve this problem correctly.
Please tell me friends.
Please tell me friends.
Vijay Kumar said:
6 years ago
@All.
tanθ=AB/AC = x/√3x.
tanθ=1/√3.
In the important formula table, they were given that the value of tan30 = 1/√3.
Hence here the value of θ becomes 30.
tanθ=AB/AC = x/√3x.
tanθ=1/√3.
In the important formula table, they were given that the value of tan30 = 1/√3.
Hence here the value of θ becomes 30.
Aditya said:
6 years ago
I think answer would be 60° because here angle of elevation of the Sun is asked.
As angle of elevation of the sun increases the length of shadow Decreases and vice versa.
As angle of elevation of the sun increases the length of shadow Decreases and vice versa.
Jabbar jr said:
2 years ago
The length of the shadow fo the tree is √3.
Here we want length of the tree only, So;
tanθ=opp/adj.
tanθ = x/√3.
θ=x/√3 => θ=1/√3.
So, the answer is θ = 30°.
Here we want length of the tree only, So;
tanθ=opp/adj.
tanθ = x/√3.
θ=x/√3 => θ=1/√3.
So, the answer is θ = 30°.
(12)
Kapil said:
1 decade ago
Angle ACB = Angle BCA
There are different ways to do same question.
they are using cot @ =AC/BC
but you can also use tan @ = perpendicular/base = AB/AC
There are different ways to do same question.
they are using cot @ =AC/BC
but you can also use tan @ = perpendicular/base = AB/AC
Siddharth said:
3 weeks ago
The length of the tree = AB, shadow of tree = CB.
Assume AB = x then CB = √3x.
Now , tanθ = AB / CB = x/√3x = 1/√3.
we know tan30° = 1/√3.
So, θ = 30°
Assume AB = x then CB = √3x.
Now , tanθ = AB / CB = x/√3x = 1/√3.
we know tan30° = 1/√3.
So, θ = 30°
(1)
Kanaga said:
1 decade ago
Hi,
I am not getting the question correctly. They have asked about the angle of elevation of sun. Why should we go for angle of elevation of tree?
I am not getting the question correctly. They have asked about the angle of elevation of sun. Why should we go for angle of elevation of tree?
Maddy said:
1 decade ago
Since you know that tan @ = P/B that is AB/AC. And the opposite of tan @ is cot@= B/P that is AC/AB.
I hope it will help you to understand.
I hope it will help you to understand.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers