Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
62 comments Page 3 of 7.
Sakthi said:
9 years ago
They asking only height of the tree. So the given answer is the correct one.
Nitin said:
9 years ago
The question says the heights of the tree is 3 times the shadow of the tree but the correct answer comes only when we take root 3 times?
Tharun said:
9 years ago
Cot 30 = tan 60.
Kshyama Sagar said:
9 years ago
Considering the above Fig.
Assume that the angle of elevation made by the Sun in the shadow of tree is < acb= θ and height of tree (AB) is = x (in meter).
According to question,
shadow of the tree is √3 times the height of the tree.
shadow of a tree(CA) will be = √3x.
tan θ = AB/AC = x/√3x.
tan θ =1/√3.
tan θ = tan 1/√3.
tan θ = tan30°.
θ = 30° (Require answer).
Assume that the angle of elevation made by the Sun in the shadow of tree is < acb= θ and height of tree (AB) is = x (in meter).
According to question,
shadow of the tree is √3 times the height of the tree.
shadow of a tree(CA) will be = √3x.
tan θ = AB/AC = x/√3x.
tan θ =1/√3.
tan θ = tan 1/√3.
tan θ = tan30°.
θ = 30° (Require answer).
Vinay said:
9 years ago
Can anyone explain me taking of angle ACB and why not ABC?
Am thinking the eye of the sun for elevation is from b.
Am thinking the eye of the sun for elevation is from b.
Madhav said:
9 years ago
Tan60 = 1/3.
Aadil said:
8 years ago
Angle = Tan inverse of( Opposite side/ Adjacent side).
So, the Final answer is 30 deg. As tan inverse of 1/root3.
So, the Final answer is 30 deg. As tan inverse of 1/root3.
Sangeethasendhil. said:
8 years ago
Cot θ = root 3.
Then θ =30°; I can't understand this step, can anyone this calculation?
Then θ =30°; I can't understand this step, can anyone this calculation?
Mahendra said:
8 years ago
Let height of the shadow = x.
Then the shadow of the is root3 times the height of the tree = root3*x.
Nnow tan θ =x/root3*x.
x,x gets cancel and 1/3 remains.
we know the tan1/3 = 30°.
Then the shadow of the is root3 times the height of the tree = root3*x.
Nnow tan θ =x/root3*x.
x,x gets cancel and 1/3 remains.
we know the tan1/3 = 30°.
Mahesh said:
8 years ago
Why cot or tan, why don't we take sine or cosine?
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