Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
30°
45°
60°
90°
Answer: Option
Explanation:

Let AB be the tree and AC be its shadow.

Let ACB = .

Then, AC = 3         cot = 3
AB

= 30°.

Discussion:
62 comments Page 2 of 7.

Dendup said:   1 decade ago
may i know how AC/AB is related to cot@??

Maddy said:   1 decade ago
Since you know that tan @ = P/B that is AB/AC. And the opposite of tan @ is cot@= B/P that is AC/AB.

I hope it will help you to understand.

XMP said:   1 decade ago
What is the value of AC & AB?

Manu said:   1 decade ago
Consider the height of the tree is 'x' m. Then the shadow is (3)^1/2. And apply tan or cot based on the relation which you want to find.

Aparna said:   1 decade ago
Why don't we consider tan 60 here?

Sanjay said:   10 years ago
Ya question has some mistake it's not 3. It's 3^1/2.

Lavanya said:   10 years ago
Guys they said shadow of the tree is root 3 times of its height that is if we take height as "x" then base is "root 3x".

If we do by using Tan then:

Tan theta = Height/Base.

= x/root 3x.

By cancelling we will get 1/root 3.

Theta = tan-1(1/root 3).

i.e theta = 30 that's it.

Shiyas said:   10 years ago
@Lavanaya.

How you cancel "x/root 3x" as "x/root3"? I think it is wrong.

Ashish kaushik said:   10 years ago
Its simple let AB = x then ac = root3x.

Tan theta = ab/ac = x/root 3x = 1/root3.

Then tan theta =1/root3 = 30 degree.

Palash said:   9 years ago
I am not getting the question's meaning. They have included two objectives (tree as well as sun) but which one should I take to solve this problem correctly.

Please tell me friends.


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