Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
63 comments Page 2 of 7.
Lory said:
6 years ago
I can't understand the question yet.
(1)
Vaibhav said:
6 years ago
Thank you all for explaining.
(1)
Gurpreet said:
5 years ago
Thanks all.
(1)
ATWONGYEIRE NELBERT said:
12 months ago
Thanks all for explaining the answer.
(1)
Idiotshere said:
2 decades ago
Help me please!.
I'm not getting here why we are saying ACB why don't BCA ?
And another is that why AC/AB why don't AB/AC = tan60 ?
I'm not getting here why we are saying ACB why don't BCA ?
And another is that why AC/AB why don't AB/AC = tan60 ?
(1)
Vijay Kumar said:
7 years ago
@All.
tanθ=AB/AC = x/√3x.
tanθ=1/√3.
In the important formula table, they were given that the value of tan30 = 1/√3.
Hence here the value of θ becomes 30.
tanθ=AB/AC = x/√3x.
tanθ=1/√3.
In the important formula table, they were given that the value of tan30 = 1/√3.
Hence here the value of θ becomes 30.
Aniket said:
8 years ago
We can also take tan instead of cot.
Amul said:
8 years ago
How can say that cot 30°? tan 60 is not compatitable at all I think sin60 or cos60 would be right choice.
Kelzhenry said:
8 years ago
AB/AC = Tanθ.
From the question,
AB/√3AB =Tanθ
1/√3 = Tanθ
θ = 30°.
From the question,
AB/√3AB =Tanθ
1/√3 = Tanθ
θ = 30°.
Biplab Gorai said:
8 years ago
Thanks for the given solution.
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