Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 5 of 15.

SAILAJA said:   1 decade ago
CI-SI=1,
T=2
R=4
P=?
SHORTCUT IS
CI-SI=P(R/1OO)^2
1=P(4/100)^2
P=625

Priya said:   1 decade ago
C.I-S.I=P(R/100)^2
IS THIS FORMULA CORRECT?

Siri said:   1 decade ago
Shortcut method: difference= sum (rate/100) ^2.

AKSHAY said:   1 decade ago
The correct formula is (ci-si) (100/r) (100/r) = p.

NOTE: (THIS FORMULA IS FOR TWO YEARS ONLY).

Pankaj parashar said:   1 decade ago
Short cut method:

si rate for 2 years=8%
ci rate for 2 years=8.16%
diff=.16% ie is equal to re 1
so 1/.16*100=625

Suresh said:   1 decade ago
Please tell me anyone why are subtract X from first step?

Ankit gupta said:   1 decade ago
Apply formula :

CI-SI= p(r/100)^2 this formula works only for t=2 years;

CI-SI = p[(r/100)^3+3(r/100)^2] for t=3 years;

Srikant Duppada said:   1 decade ago
FORMULA:

Principal x (r%/100)^2 = Difference between interests.

Manu said:   1 decade ago
The question is to find the sum of CI & SI. The answer we got is the principle, not the sum. Please correct if I am Wrong.

V panindraa said:   1 decade ago
Sum = (10,000 * difference) / r*r.

THIS FORMULA IS FOR TWO YEARS ONLY.


Post your comments here:

Your comments will be displayed after verification.