Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 4 of 15.

Pratik patel said:   1 decade ago
But. It is for only two years. I think. Not for 4;5;6 years. Try it. @Chetan.

Subhani said:   1 decade ago
Difference D = P(R*R)/10000.

Siva nandi reddy said:   1 decade ago
For 3 years p=(d*100*100*100)/(r*r(r+300)).

Amit kumar said:   1 decade ago
Sum = difference(100/rate)^t (here t=2yrs).

Sum = 1(100/4)^2 = 625.

Tarakeswararao said:   1 decade ago
Hello friend this is Tarak.

Now we have formula for finding this type of problems.

i.e D = P*(R/100)^2 if the time is 2 years.

If time is 3 years now the formula is D = P*(R/100)^2*(3+(R/100)).

Where D = Difference.
P = Principle amount.
R = Interest.

An aspirant said:   1 decade ago
Sum = Difference*(100) square/(r)square.

Prabhjot Singh said:   1 decade ago
Just equate:

CI-SI = P(R/100)(R/100) for 2 years.

CI-SI = P(R/100)(R/100)(300+R/100) for 3 years.

By these formula's it is easier to calculate the result.

Raja said:   1 decade ago
What is the shortcut formula to find differences of ci and si for 4 years and 5 years?

Siva said:   1 decade ago
Difference between 2 years = pr^2/100^2.

Ganga said:   1 decade ago
@Pankaj parashar.

Please tell me how CI rate for 2 years = 8.16%.

Please help me.


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