Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 3 of 15.
Siddhesh anavkar said:
5 months ago
CI for 2 year, 4%=1/25.
25 26
25 26
--- ---
625 676
When P = 625 CI = 51.
Calculating SI When P = 625, T = 2,R = 4.
SI = 50.
CI-SI =1.
Condition is satisfying;
P must be 625.
25 26
25 26
--- ---
625 676
When P = 625 CI = 51.
Calculating SI When P = 625, T = 2,R = 4.
SI = 50.
CI-SI =1.
Condition is satisfying;
P must be 625.
(3)
SHANKAR said:
9 years ago
SIMPLE STEP.
FORMULA :
Diff b/w SI and CI when T = 2yrs.
P = (D * 100^2)/R^2.
D =RS 1.
R = 4%.
SO, Answer is 625.
FOR DIFF B/W CI AND SI FOR 3 YRS
FORMULA
P = (D * 100^3)/R^2(300 + R).
FORMULA :
Diff b/w SI and CI when T = 2yrs.
P = (D * 100^2)/R^2.
D =RS 1.
R = 4%.
SO, Answer is 625.
FOR DIFF B/W CI AND SI FOR 3 YRS
FORMULA
P = (D * 100^3)/R^2(300 + R).
Anondo said:
9 months ago
Profit of two is the same for C and S but it is a different profit of profit last year.
So, let first-year profit x then
4%of x = 1,
x= 25.
If.
Principle y.
Then 4%of y = 25,
y= 625.
So, let first-year profit x then
4%of x = 1,
x= 25.
If.
Principle y.
Then 4%of y = 25,
y= 625.
(4)
Mjr said:
6 years ago
Si;
p = 100.
r = 4%pa,
t = 2yr,
i = 8, .
Ci;
p=100.
r=4%pa,
t=2 yr.
And; i = 8.16.
0.16 = 100,
1= 100/0.16,
= 625.
p = 100.
r = 4%pa,
t = 2yr,
i = 8, .
Ci;
p=100.
r=4%pa,
t=2 yr.
And; i = 8.16.
0.16 = 100,
1= 100/0.16,
= 625.
Mamta Srivastava said:
9 years ago
How we derive the shortcut trick for 2 or 3 years for the sum of money if the difference given b/w CI and SI? Anyone help me to clear these shortcut to improve myself. Please.
Prasanna Kumar said:
9 years ago
SI for 2 yrs = 4% +4%.
i.e * 8%.
And CI for 2 yrs = 4+4+(4*4/100) i.e 8.16% .
Then take the options,
Given difference is ci - si = 1.
8.16% (625) - 8% (625).
ie, 51- 50 = 1.
i.e * 8%.
And CI for 2 yrs = 4+4+(4*4/100) i.e 8.16% .
Then take the options,
Given difference is ci - si = 1.
8.16% (625) - 8% (625).
ie, 51- 50 = 1.
Remya said:
8 years ago
Anu deposit some money in a bank. After 6 years he got 6500rs, then after 2 years, she got 7800 rs. The how much amount will she get after 10 years?
Can anyone solve this?
Can anyone solve this?
ELISHA said:
8 years ago
Guys you have to take the square of the given percentage.
4%..................... (4%)^2 = 8.16.
=>8.16x-8x=0.16%x,
=>0.16%x=1
by solving
You will get x=625.
4%..................... (4%)^2 = 8.16.
=>8.16x-8x=0.16%x,
=>0.16%x=1
by solving
You will get x=625.
Baadshah said:
8 years ago
Shortcut method:
When the difference between SI and CI is x and rate of interest is R then,
x(100/R)^n where n is the number of years,
So 1(100/4)^2 = (25)^2 = 625.
When the difference between SI and CI is x and rate of interest is R then,
x(100/R)^n where n is the number of years,
So 1(100/4)^2 = (25)^2 = 625.
ADITYA VERMA said:
8 years ago
Short trick of this sum.
If the sum says diff. Of 2 years then apply::
P*R*R/100*100.
If the sum says diff. For 3 years then apply::
P*R*R (300+R)/100*100*100.
If the sum says diff. Of 2 years then apply::
P*R*R/100*100.
If the sum says diff. For 3 years then apply::
P*R*R (300+R)/100*100*100.
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