Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 3 of 15.

Siddhesh anavkar said:   5 months ago
CI for 2 year, 4%=1/25.

25 26
25 26
--- ---
625 676

When P = 625 CI = 51.
Calculating SI When P = 625, T = 2,R = 4.
SI = 50.
CI-SI =1.
Condition is satisfying;
P must be 625.
(3)

Divya kumari said:   11 months ago
The difference between S.I and C.I for two years is P.r^ 2/100^2.
Use this formula;
1 = p.4 * 4/100*100.
= 625 Answer.
(2)

Goutham said:   2 decades ago
Hai I am Goutham.

Can anyone help me out , why are we using -x in the step one..

Please help me out
Thanks in advance...
(1)

Name said:   1 decade ago
P x 4/100 x 4/100 = 1

P = 25*25 = 625
(1)

Ankit said:   9 years ago
Solution for CI on certain amount for 2 years is 2200 and 3 years is 3640. Find the rate?

Guys please help me.
(1)

Yogesh patil said:   6 years ago
One of the simplest way to solve difference between si and ci by using simple formula
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.
(1)

Verma said:   5 years ago
Use this to get the answer.
Sum = X(100/r)^2.
where X = C.I - S.I.
(1)

Xyz said:   2 decades ago
CI = interest- sum............
observe problem 1 . CI= 3321-3200

Gutti said:   2 decades ago
You have any shortcut method to this.

Priyanka P. said:   1 decade ago
Its p*(x/100)^2 = ans.

p=amount
x=rate


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