Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 12 of 15.
Chandan said:
8 years ago
Here, sum= (difference * 10000)/rate squre.
ADITYA VERMA said:
8 years ago
Short trick of this sum.
If the sum says diff. Of 2 years then apply::
P*R*R/100*100.
If the sum says diff. For 3 years then apply::
P*R*R (300+R)/100*100*100.
If the sum says diff. Of 2 years then apply::
P*R*R/100*100.
If the sum says diff. For 3 years then apply::
P*R*R (300+R)/100*100*100.
Hiten said:
8 years ago
Diff = pri*(r/100)sqr.
1 = x*(4/100)sqr,
1 = x*(1/25)sqr,
1 = x/625,
x=625.
1 = x*(4/100)sqr,
1 = x*(1/25)sqr,
1 = x/625,
x=625.
Hitesh said:
8 years ago
Why are we subtracting -x in the first part?
Ritu said:
8 years ago
Please, someone explains the question. At what % per annum will 625 will amount to 676 in 2 yr at c.i.
Prince said:
8 years ago
Easy question try pr^2/100^2 = difference when the time is given 2.
Pr^2 (300+r)/100^3 when the time is given 3yr.
Pr^2 (300+r)/100^3 when the time is given 3yr.
Ravi said:
8 years ago
x (100/r)^2 = 1(100/4)^2.
ELISHA said:
8 years ago
Guys you have to take the square of the given percentage.
4%..................... (4%)^2 = 8.16.
=>8.16x-8x=0.16%x,
=>0.16%x=1
by solving
You will get x=625.
4%..................... (4%)^2 = 8.16.
=>8.16x-8x=0.16%x,
=>0.16%x=1
by solving
You will get x=625.
Sneha said:
8 years ago
Difference formula for 2 years____.
Sum = Difference * (100) ^/Rate^
Then, Sum = 1*100*100 / 4*4 =625.
Sum = Difference * (100) ^/Rate^
Then, Sum = 1*100*100 / 4*4 =625.
Revathi said:
8 years ago
CI-si=p(r/100)^2 this formula applicable for more than 2 yrs also.
Am I correct?
Am I correct?
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