Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 11 of 15.

Salman said:   10 years ago
Actually the question is wrong:

It should be difference between compound and simple interest.

Since compound interest will always be larger than simple interest given the same rate and period.

Manaswini said:   10 years ago
I can't understand this please some one help me to understand this sum.

$weth@ said:   10 years ago
Is that a formula you used over there?

[x(1+4/100)2]-x? where and all we can use this?

Eshwar said:   10 years ago
CI = A-P.

A = P(1+r/100)n.

CI = P(1+r/100)n-P.

Where in above problem P = x.

Rick said:   1 decade ago
You people should add the formula of C.I in the formula section which is missing.

C.I = p[(1+r/100)^n -1].

Monalisa said:   1 decade ago
Hey guys, I have a shortcut formula for such problem:

p = d*100^2/r^2 (only for 2 yrs).

Where p = principle.
d = difference.
r = rate.

Bhupathi raju said:   1 decade ago
Any easiest method solve this problem?

Hema said:   1 decade ago
Shortcut formula P = (100/R)^T*D, D = Difference here.

= (100/4)^2*1 = 625.

Aparna said:   1 decade ago
P(1+0.04)^2-P)-P*0.08.

From the above step how did you got that P(1/625) = 1.

Can you please explain me?

Ganga said:   1 decade ago
@Pankaj parashar.

Please tell me how CI rate for 2 years = 8.16%.

Please help me.


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