Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 14)
14.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
Answer: Option
Explanation:
![]() |
15000 x | ![]() |
1 + | R | ![]() |
2 | - 15000 | ![]() |
- | ![]() |
15000 x R x 2 | ![]() |
= 96 | |
100 | 100 |
![]() |
![]() |
![]() |
1 + | R | ![]() |
2 | - 1 - | 2R | ![]() |
= 96 |
100 | 100 |
![]() |
![]() |
(100 + R)2 - 10000 - (200 x R) | ![]() |
= 96 |
10000 |
![]() |
![]() |
96 x 2 | ![]() |
= 64 |
3 |
R = 8.
Rate = 8%.
Discussion:
32 comments Page 1 of 4.
Muthu said:
1 decade ago
C.P - S.I
[p(1-r/100)^n-p ]-[(P*R*N)/100] = 96.
Where,
p=1500, n=2, R=?, C.P and S.I difference is 96.
[15000(1-r/100)^2-15000 ]-[(1500*R*2)/100] = 96 ...(1).
Now, 15000 common in above so take it out,
15000[1(1-r/100)^2 - 1 ]-[(1*R*2)/100] = 96 ...(2).
Take L.C.M. we get,
15000[(100 + R)^2 - 10000 - (200 x R)/10000] = 96 ...(3).
Where (100 + R)^2 is like (a + b)^2 = (a^2 + b^2 + 2*a*b).
(100^2 + R^2 + 2*100*R) = (10000 + R^2 + 200R).
Sub (10000 + R^2 + 200R) in eqn(3) we get,
15000[ (10000 + R^2 + 200R) - 10000 - (200 x R)/10000] = 96.
15000[ (10000 + R^2 + 200R - 10000 - 200R) /10000] = 96.
Now 10000 and 200R is cancelled, remaining.
15000[ R^2 /10000] = 96.
[15000R^2/10000] = 96.
[15R^2/10] = 96.
divide by 5 we get,
[3R^2/2] = 96.
Now keep the R^2 in left hand side and move 3/2 to right side
R^2 = 96(2/3) // 96/3 = 32.
R^2 = 32*2.
R^2 = 64 // square root of 64 is 8.
R = 8%.
[p(1-r/100)^n-p ]-[(P*R*N)/100] = 96.
Where,
p=1500, n=2, R=?, C.P and S.I difference is 96.
[15000(1-r/100)^2-15000 ]-[(1500*R*2)/100] = 96 ...(1).
Now, 15000 common in above so take it out,
15000[1(1-r/100)^2 - 1 ]-[(1*R*2)/100] = 96 ...(2).
Take L.C.M. we get,
15000[(100 + R)^2 - 10000 - (200 x R)/10000] = 96 ...(3).
Where (100 + R)^2 is like (a + b)^2 = (a^2 + b^2 + 2*a*b).
(100^2 + R^2 + 2*100*R) = (10000 + R^2 + 200R).
Sub (10000 + R^2 + 200R) in eqn(3) we get,
15000[ (10000 + R^2 + 200R) - 10000 - (200 x R)/10000] = 96.
15000[ (10000 + R^2 + 200R - 10000 - 200R) /10000] = 96.
Now 10000 and 200R is cancelled, remaining.
15000[ R^2 /10000] = 96.
[15000R^2/10000] = 96.
[15R^2/10] = 96.
divide by 5 we get,
[3R^2/2] = 96.
Now keep the R^2 in left hand side and move 3/2 to right side
R^2 = 96(2/3) // 96/3 = 32.
R^2 = 32*2.
R^2 = 64 // square root of 64 is 8.
R = 8%.
(1)
Wrick said:
7 years ago
Simply, the solution is;
15000 * [{1+(r/100)}^2-1]-(15000 * 2 * r)/100 = 96,
=> 15000[{1+(r/100)}^2-1-(2 * r)/100]= 96,
=> 15000[1+(r^2)/10000-1] = 96 where [(a+b)^2-2ab = a^2 + b^2],
=> 15000[r^2/10000] = 96,
=> r^2 = 64,
=> r = 8.
15000 * [{1+(r/100)}^2-1]-(15000 * 2 * r)/100 = 96,
=> 15000[{1+(r/100)}^2-1-(2 * r)/100]= 96,
=> 15000[1+(r^2)/10000-1] = 96 where [(a+b)^2-2ab = a^2 + b^2],
=> 15000[r^2/10000] = 96,
=> r^2 = 64,
=> r = 8.
(2)
Khyati mehta said:
4 years ago
We can directly do this by using the formula.
Difference between SI and CI for 2 years = principle *(Rate of Interest)^2
= P(R%)^2.
So here the difference is 96, principle=15000.
96 = 15000*(R/100)^2.
r = 8%.
Difference between SI and CI for 2 years = principle *(Rate of Interest)^2
= P(R%)^2.
So here the difference is 96, principle=15000.
96 = 15000*(R/100)^2.
r = 8%.
(1)
Priyanka P. said:
1 decade ago
@Anonymous
for C.I. formula is=>
p(1-r/100)^n-p
without subtracting, which amount we get is
"Principle amount+Interest"
so to get C.I. we have to subtract it..
for C.I. formula is=>
p(1-r/100)^n-p
without subtracting, which amount we get is
"Principle amount+Interest"
so to get C.I. we have to subtract it..
Ratan said:
8 years ago
Hi All ,
There is a shortcut method for this -
C.I. - S.I. = P*R^2/(100)^2.
so if we will put the values here it will be like this;
96 = 15000*R*R/10000,
64 = R*R,
So R =8.
There is a shortcut method for this -
C.I. - S.I. = P*R^2/(100)^2.
so if we will put the values here it will be like this;
96 = 15000*R*R/10000,
64 = R*R,
So R =8.
(3)
Lucky said:
1 decade ago
In 4th step how they done R^2=64 ?
If we solve it there should be R^2-200R=64 and this is a quadratic equation. Can anyone explain me how to solve this equation ?
If we solve it there should be R^2-200R=64 and this is a quadratic equation. Can anyone explain me how to solve this equation ?
Diwagar said:
2 years ago
Difference between S.I and C. I is;
D = P(R/100) ^2,
96 =15000(R/100) ^2,
(96 * 2)/3 =R^2,
64 = R^2,
Ans. R = 8.
D = P(R/100) ^2,
96 =15000(R/100) ^2,
(96 * 2)/3 =R^2,
64 = R^2,
Ans. R = 8.
(4)
Upasana said:
7 years ago
Can the difference be added to the principal to get the amount for compound interest formula?
And then by using CI formula rate can be calculated.
And then by using CI formula rate can be calculated.
Ash said:
4 years ago
Hi guys,
I will tell you the simplest method for the difference between Si and Ci sums.
Use the formula:
Difference = P*(R^2)/100^2.
I will tell you the simplest method for the difference between Si and Ci sums.
Use the formula:
Difference = P*(R^2)/100^2.
(5)
Mudasir said:
1 decade ago
It's simply p(r/100)^2
p=1500,r=x,t=2yrs
Thus
15000(x/100)^2 it finally comes out like
x^2=64
x^2=8^2
x=8
Therefore rate=8%
p=1500,r=x,t=2yrs
Thus
15000(x/100)^2 it finally comes out like
x^2=64
x^2=8^2
x=8
Therefore rate=8%
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