Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 14)
14.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
8
10
12
Cannot be determined
None of these
Answer: Option
Explanation:

15000 x 1 + R 2 - 15000 - 15000 x R x 2 = 96
100 100

15000 1 + R 2 - 1 - 2R = 96
100 100

15000 (100 + R)2 - 10000 - (200 x R) = 96
10000

R2 = 96 x 2 = 64
3

R = 8.

Rate = 8%.

Discussion:
32 comments Page 2 of 4.

Naveen said:   4 years ago
CI-SI = P(R/100)^2.
CI-SI = 96.
P = 15000.
96 = 15000(R/100)^2,
96/15000 = R^2/100^2,
0.0064 = R^2/10000,
64 = R^2,
R = 8.
(7)

A Velavan said:   10 years ago
Difference between SI and CI when 2 years = p(r/100)^2.

96 = 15000(r/100)^2.

R*r = 32*2.

R^2 = 64.

R = 8.

Himani said:   6 years ago
Simply:

sum = difference * (100/R)^2 for 2 year.
sum = {difference * (100^3)}/{R^2*(300+R)} for 3 year.
(1)

NARENDRA said:   1 decade ago
SIMPLE FORMULA FOR TWO YEARS
C.I.-S.I.=P(R/100)*(R/100)
96=15000(R/100)(R/100)
R*R=960/15=64
R=8

Ravin said:   1 decade ago
Kindly explain in 3rd step howcum -1 would be showing...is this problem solve throuGh the LCM?

Tamalika Roy said:   5 years ago
@All.

The solution is;

Difference = sum(R/100)^n => formula.
Here;
96 = 15000(r/100)^2 = 8.
(1)

Somnath said:   8 years ago
@Prawin and @Velavan.

Thank you very much for giving the simple trick for the solution.

Pratima said:   1 decade ago
Can any one provide shortcut for difference (CI-SI) questions for more than two years?

PRAWIN said:   1 decade ago
shortcut:
p = d (100/r)^2

15000 = 96*100*100/r^2

r^2 = 96*100*100/15000

r = 8.

Manish said:   1 decade ago
Apply below simple formula and get the answer easily.

Difference = P(R)^2/(100)^2.


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