Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 3)
3.
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Answer: Option
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
 R = |
 |
100 x 60 |  |
= 10% p.a. |
| 100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
| C.I. |
|
|||||||||||||
|
||||||||||||||
| = 3972. |
Discussion:
94 comments Page 6 of 10.
Pavan said:
10 years ago
I am getting confusion on this problem can anyone tell me in easy way.
Rohani said:
1 decade ago
Why we take S.I as 60 and what is the difference between S.I and C.I?
Katherin said:
5 years ago
I'm confused on using -1. Why it is used?
Please anyone explain.
Please anyone explain.
(16)
Durga said:
9 years ago
@ All, Guys your discussions are very useful. Thank you all.
Renu said:
9 years ago
10% successive of 3 years is 33.1%
33.1% of 12000.
= 3972.
33.1% of 12000.
= 3972.
Aditya said:
10 years ago
S.I is interest on Principle.
C.I is interest of interest.
C.I is interest of interest.
Aparna said:
1 decade ago
How could it come 331/1000? Shall anyone explain me please?
Ramya c said:
5 years ago
Anyone can explain me, why we are calculating for 3 years?
Rajdeep saha said:
2 years ago
C.I = {12,000(1+10/100)^3} - 12000.
=3,972 => (answer).
=3,972 => (answer).
(19)
Sangavi said:
7 years ago
When will we use -P in the compound interest formula?
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