Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 3)
3.
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Answer: Option
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
 R = |
 |
100 x 60 |  |
= 10% p.a. |
| 100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
| C.I. |
|
|||||||||||||
|
||||||||||||||
| = 3972. |
Discussion:
94 comments Page 5 of 10.
Aayushi said:
1 decade ago
Can anyone help me that why do we have to subtract the P. And when to subtract and when not to?
Lee Chong Wei said:
10 years ago
Hi can anyone explain me why CI = Amount-P if its P we can substitute the actual principal.
Sriram Manikanth said:
5 years ago
60 is interest 100 is the principle.
SI = pnr/100.
Therefor 60 = 100 * 6*r/100,
r = 10%.
SI = pnr/100.
Therefor 60 = 100 * 6*r/100,
r = 10%.
(3)
Nishu said:
2 years ago
@All
Here, -1 came from the formula of compound interest as;
C.I = Amount - Principal.
Here, -1 came from the formula of compound interest as;
C.I = Amount - Principal.
(17)
Rajeev rathor said:
7 years ago
Using pascal traingle.
= 3*10%of12000+3*10%of1200+1*10%of120,
= 3600+360+12,
= 3972.
= 3*10%of12000+3*10%of1200+1*10%of120,
= 3600+360+12,
= 3972.
Prasad said:
10 years ago
Sir question says there is an increase of 60% in amount. How can you take 60 as SI?
Satya said:
1 decade ago
@Nivedita.
Don't bother about 'P'. Think logically about r% using given data.
Don't bother about 'P'. Think logically about r% using given data.
Rahul krishna said:
6 years ago
@Sangavi we use - p because.
CI = Amount - principal.
So, CI=p(1+r/100)^n-p.
CI = Amount - principal.
So, CI=p(1+r/100)^n-p.
ROHIT said:
2 years ago
How did they get 10% as rate while calculating CI? Please explain the answer.
(5)
Arvindsamy said:
9 years ago
Guys your discussions and solutions are very useful. Thank you all guys.
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