Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 3)
3.
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Answer: Option
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
 R = |
 |
100 x 60 |  |
= 10% p.a. |
| 100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
| C.I. |
|
|||||||||||||
|
||||||||||||||
| = 3972. |
Discussion:
94 comments Page 4 of 10.
Keerthi said:
4 years ago
1200*{(1+10/100)^3 - 1}, and next step how will become?
Especially- (1200*331/1000).
Please explain to me.
Especially- (1200*331/1000).
Please explain to me.
(3)
Kal el said:
3 years ago
There is a difference between 'increase to' and 'increase by'.
So, please describe it clearly to understand.
So, please describe it clearly to understand.
(4)
Banshika said:
5 years ago
If the amount is increased by 60%. It should be 160 right?
Then why they took 60 straight to find the answer?
Then why they took 60 straight to find the answer?
Pratiksha said:
5 years ago
@Katherin,
Instead of -1 you can take principal amount( in this case -12000/-), you will get the same answer.
Instead of -1 you can take principal amount( in this case -12000/-), you will get the same answer.
(8)
Rahul krishna said:
6 years ago
Let p=100 and si=60(as amount increase to 60%).
Si=(p*r*t)/100.
Find r=?.
Then, with the help of r find ci.
Si=(p*r*t)/100.
Find r=?.
Then, with the help of r find ci.
Shub said:
7 years ago
Amount after 1st year =1200.
After 2nd year=1200 + 120.
After 3rd year= 1200 + 120+120+12.
Total = 3972.
After 2nd year=1200 + 120.
After 3rd year= 1200 + 120+120+12.
Total = 3972.
Victor said:
9 years ago
Please help me to solve this question.
Formula:
Fp=Pp(1+r) raise to power n.
if Pp=100, r=3%,n = 10.
Formula:
Fp=Pp(1+r) raise to power n.
if Pp=100, r=3%,n = 10.
Poorvajain said:
1 decade ago
CI=AMT-PRINCIPLE
So in this question princple is 100 and u hve taken principle 1 why so is it wrong.
So in this question princple is 100 and u hve taken principle 1 why so is it wrong.
Prabhakaran said:
9 years ago
Hi, can anyone explain to me why CI = Amount - P if its P we can substitute the actual principal.
Vishwanath said:
3 years ago
@Harshit.
First solve brackets, then multiply them into 3 times.
Then, You will get 1331/1000.
First solve brackets, then multiply them into 3 times.
Then, You will get 1331/1000.
(4)
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