Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 3)
3.
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Answer: Option
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
 R = |
 |
100 x 60 |  |
= 10% p.a. |
| 100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
| C.I. |
|
|||||||||||||
|
||||||||||||||
| = 3972. |
Discussion:
94 comments Page 7 of 10.
Shima said:
1 year ago
For 6 years = 60% increase.
i.e for 1 year = 10% pa.
i.e for 1 year = 10% pa.
(21)
Aashi said:
7 years ago
Please tell me how 331 is coming? Please explain me.
Harshit said:
4 years ago
How to solve (1 + 10/100) ^3?
Please explain it.
Please explain it.
(2)
Priya said:
2 decades ago
Thanks Jeeva. Now I also clear abut this problem.
Sunita Sisodiya said:
1 decade ago
Can you help with shortcut method for the same.
Vishwanath said:
3 years ago
@Keerti.
12000 * 331/1000 = 12 * 331/1 = 3972.
12000 * 331/1000 = 12 * 331/1 = 3972.
(5)
Jay said:
2 years ago
From Where this -1 came? Please explain to me.
(24)
Sandeep said:
1 decade ago
Please explain How (1+10/100)^3 is calculated?
Sandip said:
1 decade ago
C.I = Rs. (12000*(1+(10/100)^3))-12000 = 3972.
Sammy said:
9 years ago
Thank you so much for explaining the solution.
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