Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 5)
5.
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:
2
2 1
2
3
4
Answer: Option
Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000 1 + 7 n = 34347
100

107 n = 34347 = 11449 = 107 2
100 30000 10000 100

n = 2 years.

Discussion:
46 comments Page 4 of 5.

Usha said:   1 decade ago
C.I will be the 4347.

C.I = AMOUNT-PRINCIPAL.

PRINCIPAL = 30,000.

4347 = AMOUNT-30000.

AMOUNT = 4347+30000 = 34347.

AMOUNT = P(1+R/100)^n.

34347 = 30000(1+7/100)^n.

34347/30000 = (107/100)^n.

Sumit P. said:   1 decade ago
Sorry Guys but it should;

11449 / 10000 // 34347 / 30000 is multiplied and divide by 3.

Hence, Now 11449 and 10000 are squares of 107 and 100 resp.

Thus(107 / 100)^ 2. Thus n = 2.

Anshu said:   1 decade ago
30000*7/100 = 2100 - year 1.

30000+2100 = 32100*7/100 = 2247 - year 2.

Now add 2100+2247 = 4347 which is 2 years.

Hafsa ali said:   1 decade ago
Why we add 30,000 and 4347?

Arpita Dey said:   1 decade ago
How (107/100)^t = 34347/30000.

t=2?

I forgot the conversion.

Anurag Nath said:   9 years ago
@Hitendra.

(107/100)n = 11449/10000.
=> 107 * 107/100 * 100 = 11449/10000.
=> (107/100)2 = 11449/10000 [Here n = 2].

Therefore n=2.

Fizna said:   1 decade ago
Can anyone say the exact formula for finding the period?

Hitendra said:   1 decade ago
How to calculate (107/100)^t = 34347/30000?

Rajnish said:   1 decade ago
Hi guys,

I think (107/100)^t is not easy to find without using calculator.

So, I want advice you play hit and trial. Take t = 1, t = 2, ..... and match your option.

TEJAS said:   1 decade ago
Why 34347/30000?


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