Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 13)
13.
The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is:
Answer: Option
Explanation:
| S.I. = Rs |  |
1200 x 10 x 1 |  |
= Rs. 120. |
| 100 |
| C.I. = Rs. |  |
1200 x | |
1 + | 5 | |
2 | - 1200 |  |
= Rs. 123. |
| 100 |
Difference = Rs. (123 - 120) = Rs. 3.
Discussion:
53 comments Page 3 of 6.
Hrishi said:
9 years ago
Hi friends this might be help you.
In both the cases we should take time 1 year means t = 1 for S.I. and n = 1 for C.I.
But half-yearly data is only given for C.I so, the formula changed for C.I .as per compounded half-yearly.
In both the cases we should take time 1 year means t = 1 for S.I. and n = 1 for C.I.
But half-yearly data is only given for C.I so, the formula changed for C.I .as per compounded half-yearly.
Revathi jiii said:
9 years ago
For one year there both SI and CI remains same. Then how come its possible?
Dhakshinamoorthi said:
9 years ago
Friends,
They told to calculate for 1 year.
Given data is half yearly.
The reason why they calculated for SI without changing the rate of interest is as in the concept of SI the interest rate won't change (constant) so they kept same.
While in CI they changed because it won't be constant. This is the reason guys.
They told to calculate for 1 year.
Given data is half yearly.
The reason why they calculated for SI without changing the rate of interest is as in the concept of SI the interest rate won't change (constant) so they kept same.
While in CI they changed because it won't be constant. This is the reason guys.
(1)
Dhairya said:
9 years ago
Just use this formula:
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
(1)
Praveen chauhan said:
9 years ago
Just used this formula:
Diffrence = (P * R * R/100 * 100).
Given P = 1200, half yearly compounded so rate becomes half and time becomes double.
Earlier - T = 1, R = 10%.
Now T = 2, R = 5%.
(1200 * 5 * 5/100 * 100) = Rs 3.00.
I hope you will understand better!
Thanks.
Diffrence = (P * R * R/100 * 100).
Given P = 1200, half yearly compounded so rate becomes half and time becomes double.
Earlier - T = 1, R = 10%.
Now T = 2, R = 5%.
(1200 * 5 * 5/100 * 100) = Rs 3.00.
I hope you will understand better!
Thanks.
Himesh said:
9 years ago
Why do we need to calculate amount?
According to the question they only asked for difference between CI and SI.
According to the question they only asked for difference between CI and SI.
K.BHARGAVI said:
9 years ago
for one year S.I is ptr/100,
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
Haritha said:
9 years ago
Do we have any other method to solve this problem? If yes means, please tell me.
Sandy said:
9 years ago
Yes @Santhiya you are upto the point. Anyhow SI gonna be the fixed interest for the months.
Santhiya said:
9 years ago
Yeah. I'm clear. Out off all the above solutions, I could say yours is the best.
S.I calculation will be same if we calculate interest for 1 year & 10% or with summation of two six months with 5% interest. Right?
S.I calculation will be same if we calculate interest for 1 year & 10% or with summation of two six months with 5% interest. Right?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers