Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 13)
13.
The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is:
Answer: Option
Explanation:
| S.I. = Rs |  |
1200 x 10 x 1 |  |
= Rs. 120. |
| 100 |
| C.I. = Rs. |  |
1200 x | |
1 + | 5 | |
2 | - 1200 |  |
= Rs. 123. |
| 100 |
Difference = Rs. (123 - 120) = Rs. 3.
Discussion:
53 comments Page 2 of 6.
K.BHARGAVI said:
9 years ago
for one year S.I is ptr/100,
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
Salim halari said:
1 decade ago
In simple interest, we charge interest on Principle amount only.
but in compund interest we charge interst on principle as well as interest recieved.
if you take R=5, then u have to take n=2, ans remain same.
but in compund interest we charge interst on principle as well as interest recieved.
if you take R=5, then u have to take n=2, ans remain same.
Shruthi Mishra said:
1 decade ago
While calculating simple interest why we hav'nt considered half yearly. It has been calculate for yearly but compound interest is calculated for half yearly.
Bharath said:
1 decade ago
Simple Interest (S.I.):
If the interest on a sum borrowed for certain period is reckoned uniformly, then it is called simple interest.
So pnr/100 is used.
If the interest on a sum borrowed for certain period is reckoned uniformly, then it is called simple interest.
So pnr/100 is used.
Arjun said:
6 years ago
SI = 120
Given P = 1200, half-yearly compounded so rate becomes half and time becomes double.
1200 * 10.25/100 = 123,
CI-SI= 123-120 = 3.
Given P = 1200, half-yearly compounded so rate becomes half and time becomes double.
1200 * 10.25/100 = 123,
CI-SI= 123-120 = 3.
(2)
Deekshit said:
1 decade ago
Given that C.I formula for half-yearly as p[1+ (r/2) /100]^2n.
Then 2n means 2*1/2=1 but you are taken it as power 2 how it's possible?
Then 2n means 2*1/2=1 but you are taken it as power 2 how it's possible?
(1)
ARCHISA DAS said:
5 years ago
5/100 is given in the formula. In the formula, there is p*(1+r/100)^n.
Here the rate is given 5% so it has come 5/100.
Hope this helps.
Here the rate is given 5% so it has come 5/100.
Hope this helps.
(1)
Dhairya said:
9 years ago
Just use this formula:
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
(1)
Skywalker said:
1 month ago
S.I = 2 (PRT)/100 ,
T = 0.5,
= 120.
A = P(1+ R/2/100)^2
= 1323.
Then C.I = 1323 - 1200,
= 123
And we get, S.I - C.I = 3.
T = 0.5,
= 120.
A = P(1+ R/2/100)^2
= 1323.
Then C.I = 1323 - 1200,
= 123
And we get, S.I - C.I = 3.
Binnu said:
1 decade ago
Compound interest = p[1+(r/2)/100]^2n for half yearly.
So here they gave r=10% so r/2=5 according to the formulae.
So here they gave r=10% so r/2=5 according to the formulae.
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