Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 13)
13.
The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is:
Answer: Option
Explanation:
| S.I. = Rs |  |
1200 x 10 x 1 |  |
= Rs. 120. |
| 100 |
| C.I. = Rs. |  |
1200 x | |
1 + | 5 | |
2 | - 1200 |  |
= Rs. 123. |
| 100 |
Difference = Rs. (123 - 120) = Rs. 3.
Discussion:
53 comments Page 2 of 6.
Dhakshinamoorthi said:
10 years ago
Friends,
They told to calculate for 1 year.
Given data is half yearly.
The reason why they calculated for SI without changing the rate of interest is as in the concept of SI the interest rate won't change (constant) so they kept same.
While in CI they changed because it won't be constant. This is the reason guys.
They told to calculate for 1 year.
Given data is half yearly.
The reason why they calculated for SI without changing the rate of interest is as in the concept of SI the interest rate won't change (constant) so they kept same.
While in CI they changed because it won't be constant. This is the reason guys.
(1)
Dhairya said:
10 years ago
Just use this formula:
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
(1)
Deekshit said:
1 decade ago
Given that C.I formula for half-yearly as p[1+ (r/2) /100]^2n.
Then 2n means 2*1/2=1 but you are taken it as power 2 how it's possible?
Then 2n means 2*1/2=1 but you are taken it as power 2 how it's possible?
(1)
ARCHISA DAS said:
6 years ago
5/100 is given in the formula. In the formula, there is p*(1+r/100)^n.
Here the rate is given 5% so it has come 5/100.
Hope this helps.
Here the rate is given 5% so it has come 5/100.
Hope this helps.
(1)
K.BHARGAVI said:
10 years ago
for one year S.I is ptr/100,
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
Revathi jiii said:
10 years ago
For one year there both SI and CI remains same. Then how come its possible?
Praveen chauhan said:
10 years ago
Just used this formula:
Diffrence = (P * R * R/100 * 100).
Given P = 1200, half yearly compounded so rate becomes half and time becomes double.
Earlier - T = 1, R = 10%.
Now T = 2, R = 5%.
(1200 * 5 * 5/100 * 100) = Rs 3.00.
I hope you will understand better!
Thanks.
Diffrence = (P * R * R/100 * 100).
Given P = 1200, half yearly compounded so rate becomes half and time becomes double.
Earlier - T = 1, R = 10%.
Now T = 2, R = 5%.
(1200 * 5 * 5/100 * 100) = Rs 3.00.
I hope you will understand better!
Thanks.
Hrishi said:
10 years ago
Hi friends this might be help you.
In both the cases we should take time 1 year means t = 1 for S.I. and n = 1 for C.I.
But half-yearly data is only given for C.I so, the formula changed for C.I .as per compounded half-yearly.
In both the cases we should take time 1 year means t = 1 for S.I. and n = 1 for C.I.
But half-yearly data is only given for C.I so, the formula changed for C.I .as per compounded half-yearly.
Shruti said:
9 years ago
Why we have raised the power to 2 in calculating CI?
Nitish reddy said:
9 years ago
Here we are taking for only single half year so, n=1 then 2n=2*1=2.
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