Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 14)
14.
At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?
Answer: Option
Explanation:
At 4 o'clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min.
50 min. spaces are gained in | ![]() |
60 | x 50 | ![]() |
6 | min. |
55 | 11 |
![]() |
6 | min. past 4. |
11 |
Discussion:
55 comments Page 3 of 6.
Vidur said:
9 years ago
Find the time between 5 and 6 o'clock when the two hands of the clock are 6 minutes spaces apart.
Can anyone help me to solve this?
Can anyone help me to solve this?
Parul saxena said:
10 years ago
Why 30-20=10 is not considered as it is done in question number 6?
Sree said:
10 years ago
54 6/11 min. past 4 how?
Jayesh said:
10 years ago
Hi all,
Can someone explain me how is come space 30 and 55 min?
Can someone explain me how is come space 30 and 55 min?
Akhila said:
10 years ago
Please explain anyone how the answer is 54/12 from (60/55*50).
Priyanka said:
10 years ago
If we solve by the method of angle difference between hour hand and minute hand, there has to be a difference of 180 degrees for the hands to be opposite.
So I applied this in the equation. If they align 180 degrees opposite to each other after 'x' minutes, then degrees traversed by hour hand will be x*6 and that of hour hand will be (10*4) + (0.5*x).
Taking the difference, the equation formed will be 6x-40-0.5x = 180. Solving this equation gives x=40. So answer should be 40 minutes pas 4.
So I applied this in the equation. If they align 180 degrees opposite to each other after 'x' minutes, then degrees traversed by hour hand will be x*6 and that of hour hand will be (10*4) + (0.5*x).
Taking the difference, the equation formed will be 6x-40-0.5x = 180. Solving this equation gives x=40. So answer should be 40 minutes pas 4.
Raju said:
10 years ago
How 4 past come after dividing?
SACHIN PACHAURI said:
1 decade ago
Angle = 11min/2-30hour.
4 opposite direction angle is 180.
Between 4 and 5 o clock hour is 4.
You will get the min.(answer).
TRICK OF THIS TYPE OF QUESTION.
4 opposite direction angle is 180.
Between 4 and 5 o clock hour is 4.
You will get the min.(answer).
TRICK OF THIS TYPE OF QUESTION.
Kiran said:
1 decade ago
-> Imagine if both the hands are 12 i.e time is 12:00 then at 1:00 -> Hour hand will be at 1:00 .
-> Minute hand will be at 12 again.Therefore the space gained by minute hand over hour hand is 55 min in 1 hour,i.e. 55 min in 60 min i.e logical data which is used in all problems.
-> Coming to the problem,the hour hand is at 4:00 and minute hand is at 12,therefore to cross hour hand the minute hand has to gain 20 min spaces i.e it means it has to move 20 min forward.
-> Between 4:00 and 5:00 if the hour hand and minute have to be in opposite directions,then hour hand will be at 5:00 and minute hand will be 55 then it has gain 30 minutes more.
-> Totally it has to gain 20+30=50 minutes.
-> If 55->60 then 50->? Ans = 54 6/11 min past 4 they will be in opposite directions.
-> Minute hand will be at 12 again.Therefore the space gained by minute hand over hour hand is 55 min in 1 hour,i.e. 55 min in 60 min i.e logical data which is used in all problems.
-> Coming to the problem,the hour hand is at 4:00 and minute hand is at 12,therefore to cross hour hand the minute hand has to gain 20 min spaces i.e it means it has to move 20 min forward.
-> Between 4:00 and 5:00 if the hour hand and minute have to be in opposite directions,then hour hand will be at 5:00 and minute hand will be 55 then it has gain 30 minutes more.
-> Totally it has to gain 20+30=50 minutes.
-> If 55->60 then 50->? Ans = 54 6/11 min past 4 they will be in opposite directions.
(1)
Nutan said:
1 decade ago
How it 20 min spaces comes?
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