Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 15)
15.
At what time between 9 and 10 o'clock will the hands of a watch be together?
Answer: Option
Explanation:
To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.
55 min. spaces gained in 60 min.
45 min. spaces are gained in | ![]() |
60 | x 45 | ![]() |
1 | min. |
55 | 11 |
![]() |
1 | min. past 9. |
11 |
Discussion:
48 comments Page 3 of 5.
Smita said:
10 years ago
Past 9n means?
Abhishek said:
10 years ago
@Kapil.
Awesome man done in the most basic way manner as possible. Really appreciate your work.
Awesome man done in the most basic way manner as possible. Really appreciate your work.
Aarthi said:
10 years ago
Can you tell me the correct explanation?
Jeet said:
10 years ago
In Q6 at 7, they are 25 mins apart, but in this Q at 9 they are 45 mins apart, is the angle measured clockwise/ anti clockwise?
A k singh said:
1 decade ago
What master formula you are giving its not applicable to a single question we are doing. All the time its having negative sign error. I don't think so that is the master formula but can say this is confusing the whole concept we read till now.
Chandresh said:
1 decade ago
You can try this way also.
360 = 30(10)-(11/2)m.
360-300 = (11/2)m.
(60*2)/11 = m.
m = 120/11;
Now just do: 60-(120/11) = 540/11 = 49.1/11.
360 = 30(10)-(11/2)m.
360-300 = (11/2)m.
(60*2)/11 = m.
m = 120/11;
Now just do: 60-(120/11) = 540/11 = 49.1/11.
Niraj kumar said:
1 decade ago
When the hands of watch together at that time it is obvious that angle made by hour's hand = angle made by minute's hand.
Let us assume both hand meet at time (9+x/60), where x = minute.
Now, (9+x/60)*360/12=x*360/60 (angle made by both hand).
After solving this equation, we find x=540/11. So ans=9hr, 540/11min. i.e = Option C.
Let us assume both hand meet at time (9+x/60), where x = minute.
Now, (9+x/60)*360/12=x*360/60 (angle made by both hand).
After solving this equation, we find x=540/11. So ans=9hr, 540/11min. i.e = Option C.
(2)
Rossy said:
1 decade ago
Can someone please explain me, what is the main concept used to solve this problem?
V.k said:
1 decade ago
Total distance the minute hand cover with respect to hour hand is 270'
And the relative speed is 5.5.
So the time to cover is,
270/5.5 = 540/11.
And the relative speed is 5.5.
So the time to cover is,
270/5.5 = 540/11.
Inoo said:
1 decade ago
What does this means 55 min. spaces gained in 60 min ? what does spaces here means?
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