Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 15)
15.
At what time between 9 and 10 o'clock will the hands of a watch be together?
45 min. past 9
50 min. past 9
49 1 min. past 9
11
48 2 min. past 9
11
Answer: Option
Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.

55 min. spaces gained in 60 min.

45 min. spaces are gained in 60 x 45 min or 49 1 min.
55 11

The hands are together at 49 1 min. past 9.
11

Discussion:
48 comments Page 1 of 5.

Sivanandhini chandrasekar said:   3 years ago
Formula :
Θ = |11M/2 - 30H|.
0⁰=|11M/2 - 30*9|.
= 11M/2 - 270.
0⁰+270⁰=11M/2.
270*2/11=M.
540/11=M.
M = 49 1/11.
(6)

Nikhil B said:   6 years ago
@All.

θ = (11m/2) - 30h is a standard formula.
(4)

Saranya said:   4 years ago
55 = 60 min.
45 = x.
X= 60*45\55.
X = 540/11.
X = 49 1/11 past 9.
(3)

Akhilesh said:   1 decade ago
My solution is:

Both the hands will meet somewhere between 9 and 10 i.e after the minute hand has reached 9 ( after 45 minutes). In these 45 mins the hour hand must also have traveled forward by some angle.

The angles covered by the hour hand in 45 mins will be 22.5. (how? in one min it covers 1/2 that's why!).

Now, let's suppose it takes another x mins for both of them to reach the point where they will coincide.
The angle traveled by hour hand will be x/2 and by the minute hand will be 6x.

Now in order to coincide with the hour hand, the minute hand has to cover the total angle the hour hand has moved forward.

So, 6x = x/2 + 22.5.
(3)

Niraj kumar said:   1 decade ago
When the hands of watch together at that time it is obvious that angle made by hour's hand = angle made by minute's hand.

Let us assume both hand meet at time (9+x/60), where x = minute.

Now, (9+x/60)*360/12=x*360/60 (angle made by both hand).

After solving this equation, we find x=540/11. So ans=9hr, 540/11min. i.e = Option C.
(2)

Suman said:   5 years ago
Thanks for explaining @Akhilesh.
(2)

Vinayak said:   8 years ago
How does 60/55*45 become 49 1/11?

Please if anybody can explain this?
(2)

Saurabh Kumar Meena said:   2 years ago
θ angle gained from by hrs clock at the time of meet from the past 9.
θ= [(45+M)/60] *30 30 degree for each hour.
θ = M/5 *30 30 degree Minutes hand move every 5 min.
So, equate them you'll have.
M= 45/11.
So meet time will be 45+M;
(1)

Kapil said:   1 decade ago
It's very simple..

in 12 hour a hour hand gains angle= 360 degree
so in one hour it will gain = 360/12 = 30 degree

similarly,

in 60 minutes a minute hand gains = 360 degree
so in 1 minute it will gain = 360/60= 6 degree

so angle gain by hour hand at any time = 30*[y+(x/60)] degree
& angle gain by minute hand=6*x degree

where y=no. of hour (in this question it is '9')
&
x=minutes after the y O' clock..

angle gained by hour hand should be Equuleus to minute hand..

=> 30*[9+(x/60)]=x*6
=> 270+ x/2=6x
=> 540+ x=12x
=> 11x= 540
=> x= 49 1/11
(1)

Irfan Qureshi said:   8 years ago
Formula : (11/2)M - 30*H = 0.

We have to find min so put H and get M.

M=min.
H=Hour.
put the value and get the answer in Min.


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