# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 15)

15.

At what time between 9 and 10 o'clock will the hands of a watch be together?

Answer: Option

Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.

55 min. spaces gained in 60 min.

45 min. spaces are gained in | 60 | x 45 | min or 49 | 1 | min. | |

55 | 11 |

The hands are together at 49 | 1 | min. past 9. |

11 |

Discussion:

47 comments Page 1 of 5.
Sivanandhini chandrasekar said:
12 months ago

Formula :

Θ = |11M/2 - 30H|.

0⁰=|11M/2 - 30*9|.

= 11M/2 - 270.

0⁰+270⁰=11M/2.

270*2/11=M.

540/11=M.

M = 49 1/11.

Θ = |11M/2 - 30H|.

0⁰=|11M/2 - 30*9|.

= 11M/2 - 270.

0⁰+270⁰=11M/2.

270*2/11=M.

540/11=M.

M = 49 1/11.

(6)

Nikhil B said:
4 years ago

@All.

θ = (11m/2) - 30h is a standard formula.

θ = (11m/2) - 30h is a standard formula.

(4)

Akhilesh said:
8 years ago

My solution is:

Both the hands will meet somewhere between 9 and 10 i.e after the minute hand has reached 9 ( after 45 minutes). In these 45 mins the hour hand must also have traveled forward by some angle.

The angles covered by the hour hand in 45 mins will be 22.5. (how? in one min it covers 1/2 that's why!).

Now, let's suppose it takes another x mins for both of them to reach the point where they will coincide.

The angle traveled by hour hand will be x/2 and by the minute hand will be 6x.

Now in order to coincide with the hour hand, the minute hand has to cover the total angle the hour hand has moved forward.

So, 6x = x/2 + 22.5.

Both the hands will meet somewhere between 9 and 10 i.e after the minute hand has reached 9 ( after 45 minutes). In these 45 mins the hour hand must also have traveled forward by some angle.

The angles covered by the hour hand in 45 mins will be 22.5. (how? in one min it covers 1/2 that's why!).

Now, let's suppose it takes another x mins for both of them to reach the point where they will coincide.

The angle traveled by hour hand will be x/2 and by the minute hand will be 6x.

Now in order to coincide with the hour hand, the minute hand has to cover the total angle the hour hand has moved forward.

So, 6x = x/2 + 22.5.

(3)

Niraj kumar said:
10 years ago

When the hands of watch together at that time it is obvious that angle made by hour's hand = angle made by minute's hand.

Let us assume both hand meet at time (9+x/60), where x = minute.

Now, (9+x/60)*360/12=x*360/60 (angle made by both hand).

After solving this equation, we find x=540/11. So ans=9hr, 540/11min. i.e = Option C.

Let us assume both hand meet at time (9+x/60), where x = minute.

Now, (9+x/60)*360/12=x*360/60 (angle made by both hand).

After solving this equation, we find x=540/11. So ans=9hr, 540/11min. i.e = Option C.

(2)

Vinayak said:
6 years ago

How does 60/55*45 become 49 1/11?

Please if anybody can explain this?

Please if anybody can explain this?

(2)

Saranya said:
2 years ago

55 = 60 min.

45 = x.

X= 60*45\55.

X = 540/11.

X = 49 1/11 past 9.

45 = x.

X= 60*45\55.

X = 540/11.

X = 49 1/11 past 9.

(1)

Suman said:
3 years ago

Thanks for explaining @Akhilesh.

(1)

Aarthi said:
9 years ago

Can you tell me the correct explanation?

Abhishek said:
9 years ago

@Kapil.

Awesome man done in the most basic way manner as possible. Really appreciate your work.

Awesome man done in the most basic way manner as possible. Really appreciate your work.

Smita said:
9 years ago

Past 9n means?

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