Aptitude - Chain Rule - Discussion

5/8 of the work is completed in 10 days.
So we get the remaining work = (1-5/8).
= 3/8.
Completing work is directly proportional to days.

Hence direct proportion where x/y = constant.
Let we take the time taken to complete 3/8 be x.
And therefore = 10/(5/8) = 16,
for 3/8=8x/3,
thus 8x/3=16,
8x = 48,
and x = 6days.

5/8 of the work could be completed in 10 days.
So, full work could be completed in 10*8/5 = 16 days.
Extra days = 16 -10 = 6 days.

@All.

Simply;

First of all, we need to divide 5 by 10, the answer will be 0.5/half so we need to draw two lines for each day, for ex ll-1,ll-2 etc.

And after it comes to 5 just continue drawing two lines for a day (so we will do like this- ll-6, ll-7 and ll-8 )

Now we need to see the number of lines we have drawn, that is 6, then the answer will be 6.

Thank you.

5/8 in 10 days.

So remaining 3/8.
10*3/8 ÷ 5/8 = 10 * 3 * 8/8 * 5 = 6 days.

He completes 5/8 of the work in 10 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.

He completed 10 days of work.
16-10= 6 days.

He completes 5/8 of the work in 10 days.
He can complete the work in,
8/5 * 10 days,
= 80/5 days.
= 16 days.

He completed 10 days of work.
16 - 10 = 6 days.