Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes 
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Answer: Option
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = |  |
1 - | 5 |  |
= | 3 |
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x |  |
5 | x x = | 3 | x 10 |
| 8 | 8 | 8 | 8 |
 x = |
|
3 | x 10 x | 8 | |
| 8 | 5 |
x = 6.
Discussion:
36 comments Page 3 of 4.
Gokul raj said:
9 years ago
The work of 5 parts done in 10 days.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
Ram said:
9 years ago
Total work of job = 8,
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Pavan Power star PK fan said:
9 years ago
He takes 10 days to complete 5/8 of the job.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
Zareena said:
8 years ago
5/8 job = 10 days,
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
Ram said:
8 years ago
Look another eg;
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
Sowmiya said:
8 years ago
Very nice explanation @Bhadra.
Shubham said:
7 years ago
A garrison of 750 men has provision for 20 weeks if, at the end of 4 weeks, they are reinforced by 450 men, how long the provision will last?
How to solve this by using the chain rule? Please help me.
How to solve this by using the chain rule? Please help me.
Venkat Ravi said:
7 years ago
Consider a job value is 100(not given).
8/3 of work is done in 10 days then,
(8/3)*100 = 62.5(ie.,62.5% of work is completed in 10 days then the remaining work will be 37.5).
For 10 days 67.5.
For single day=(67.5/10)=6.75(ie.,per day work).
Remaining days=(remaining work/per day work) = (37.5/6.75) = 6 days.
8/3 of work is done in 10 days then,
(8/3)*100 = 62.5(ie.,62.5% of work is completed in 10 days then the remaining work will be 37.5).
For 10 days 67.5.
For single day=(67.5/10)=6.75(ie.,per day work).
Remaining days=(remaining work/per day work) = (37.5/6.75) = 6 days.
RAJAN said:
6 years ago
He completed 5 jobs out of 8, in 10 days so that means he completed 1 job in 2 days and to complete 3 more jobs (8-5=3) and he will take 6 days (3x2=6).
(2)
Pujan Das said:
6 years ago
5/8 is completed in 10 days.
Hence, 1 (100%) will be completed in (10*8)/5 = 16 days.
The rate of work remains constant. (important point).
Thus, Remaining days = total days - elapsed = 16 - 10 = 6 days.
Hence, 1 (100%) will be completed in (10*8)/5 = 16 days.
The rate of work remains constant. (important point).
Thus, Remaining days = total days - elapsed = 16 - 10 = 6 days.
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