Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 9 of 22.
Shiva kumar said:
1 decade ago
Why are you taking nearest leaf year as 2000, 2004 is also leap year right?
Why don't you take 2004 as nearest leap year? Explain please.
Why don't you take 2004 as nearest leap year? Explain please.
Yamini matiyali said:
3 years ago
28may2006.
2005
[2000] and[5]
[0] leap year [1]leap year+[4] normal year.
[1*2+4*1] + [3+0+3+2+28].
=42.
42/7.
0 remainder
Sunday Ans.
2005
[2000] and[5]
[0] leap year [1]leap year+[4] normal year.
[1*2+4*1] + [3+0+3+2+28].
=42.
42/7.
0 remainder
Sunday Ans.
(35)
Alla said:
2 years ago
From the remaining five years, what criteria did you use to say there 4 ordinary years and 1 leap year?
Anyone, please explain to me.
Anyone, please explain to me.
(11)
Kaybee said:
9 years ago
CAN YOU PLEASE HELP ME?
If I was born in 1984, no leap year and first day was Tuesday them how many Tuesdays are there in that year?
If I was born in 1984, no leap year and first day was Tuesday them how many Tuesdays are there in that year?
Bhawesh Agrawal said:
1 decade ago
Leap year comes once in every 4 year.
So in 75 years there will be 75/4 i.e. 18 leap years and the rest 75-18 = 57 ordinary years.
So in 75 years there will be 75/4 i.e. 18 leap years and the rest 75-18 = 57 ordinary years.
Ravindra reedy said:
1 decade ago
Suppose we have 23days at this time find odd days?
Ans:
No of days is divisible by 7 then we get odd days.
23/7=2.
2 odd days.
Ans:
No of days is divisible by 7 then we get odd days.
23/7=2.
2 odd days.
Bharathi said:
9 years ago
Please help me guys. First how to find odd & even no in the month & year. Then say how to solve this kind of problems?
Venkat said:
1 decade ago
I am not getting this odd days. Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Can you please explaine me?
Can you please explaine me?
Sanjeet said:
1 decade ago
@Vijay singh your answer is right and if you observe it carefully you will understand how 400 is having zero Odd days.
Rakhi said:
1 decade ago
I can't understand this step plz explain it?? 5=(5/4)leap yr+[5-1]ordinary day
=1 leap year+4 ordinary day
=1 leap year+4 ordinary day
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers