Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Thursday
Friday
Saturday
Sunday
Answer: Option
Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan.  Feb.   March    April    May 
(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Discussion:
214 comments Page 10 of 22.

Sindhu said:   2 decades ago
What are these odd days. I am unable to understand this problems? so if possible could you explain in a simple way.

Naveen kumar said:   1 decade ago
If in the last step I get "6" which day I consider, because you don't give no week day for "6".

Priya said:   1 decade ago
Yes revathi I'm agree with you. Pavithra your example is wrong.

2006-1900=106 its not 16. If ok can you explain.

Ajay reddy said:   1 decade ago
1st jan 2000 is which day of the week?

Zero odd days so it should be sunday but in real calendar it is saturday ?

Komal said:   1 decade ago
Can someone please explain 'mathematically' the solution for this problem and not by codes. Thanks in advance.

Ishwar choudhary said:   6 years ago
I think there should be (2000+6) year+jan Feb, Mar, April and 28 May. It gives 1 odd day and answer is Monday.

I m Zero said:   1 decade ago
@Dechen.

Simply we need to come till 2006 so,

Means 1600+400 = 2000.

Then remaining 2001, 2002, ....2006.

Praveen said:   9 years ago
Guys simply follow Deena's method. It is very simple and applicable for all kind of problems in calendars.

Shawisk said:   1 decade ago
@Deena.

What we write instead for 1900 if the date is 13 may 1666

For = 28+2+(2006-1900)+(2006-1900)/4.

Komal bhat said:   3 years ago
Day = date +month code +century code + year + leap year ÷ 7.
Day = 28+2+6+6+1÷7 = 1.
And 1 = Sunday.
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