Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Thursday
Friday
Saturday
Sunday
Answer: Option
Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan.  Feb.   March    April    May 
(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Discussion:
214 comments Page 11 of 22.

Akshay Chavda said:   5 years ago
Day --> +28
month code --> +2
year--> + 6
yr/4 --> +1
-----
37/7 = 2 odd days - 1 =1 .

It is Sunday.

Aman said:   1 decade ago
Odd days means when you divide by 7 to get the no of weeks the remainder left is known to be odd days.

Tamil said:   1 decade ago
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

I don't get this step could anyone help me?

Madhu said:   1 decade ago
How can we say 0 is sunday 1 is monday, 2 tues day, . How can we know the jan 1st 2006 week day?

Sonam Yangki said:   1 decade ago
Why do we take 1600 and 400? What is the relation of these two years particularly with the May?

Jugal said:   1 decade ago
I am totally confused in calander question. Then please expain in a easy lang if any one can.

Adishrey said:   1 decade ago
Odd days= (that particular year) /7, the remainder that you get is the no.of odd days in it.

Dalsukh said:   9 years ago
In simple calculation.

28/7 = 4.

The answer is four then remainder is 0. So it was Sunday.

ARNAB KAMILYA said:   3 months ago
0 + 2 + 6 + 1 = 9,
9/7 reminder is 2,
2 + 6 = 8.
8/7 reminder 1.
So, it is Sunday = answer.
(1)

M.Vamshi said:   1 decade ago
Is there any easiest method to calculate day plz i cant understood the odd day or even day


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