Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 12 of 22.
Anjali said:
1 decade ago
Too many different month codes used to do the calculation in the above answer figures !
Mounika said:
10 years ago
Why the no. of odd days of 400 and 1600 are zero? Why not 2 they are leap years right?
MANOJ said:
9 years ago
What's that thing that once a year twice a week for four months and a day is 6 times?
Jyoti said:
7 years ago
@Deena.
Kindly help me to solve and find the day for 1 April 2001 using your tricks.
Kindly help me to solve and find the day for 1 April 2001 using your tricks.
Yasar said:
1 decade ago
Please explain how the odd days of 400 and 1600 are 0 and the odd days of 300 is 15.
Rupesh said:
3 years ago
Why not consider 2004 is the leap year why are you starting with the 2000 leap year?
(16)
G.M.L.GENATUS said:
1 decade ago
Every 400 years we consider as 0.
So 1200,1600,2000,2400 years take it as 0 value.
So 1200,1600,2000,2400 years take it as 0 value.
Gani said:
1 decade ago
@Deena
I got the solution for this type of problem
Thanks for the useful formula.
I got the solution for this type of problem
Thanks for the useful formula.
Moni said:
8 years ago
In the formula type (2006-1990) is 106 only, answer comes when we substitute 106.
Vishnu said:
7 years ago
What was the day of the week on 28th August 2016?
Please explain by this method.
Please explain by this method.
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