Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 13 of 22.
Charan said:
1 decade ago
What is mean by odd days I can't understand can you please explain it in brief?
Bitupi said:
1 decade ago
I can't understand this problem. Please explain in simple. What is the odd no?
Ahmef said:
9 years ago
Hi @Deena.
Your explanation is the best method to solve the calendar problem.
Your explanation is the best method to solve the calendar problem.
Sanjana said:
5 years ago
Why are 400 and 1600 yrs taken, why not other years? Please anyone explain me.
Shubham singh said:
9 years ago
Dividing any number by 7 that gives you as a reminder which is know odd no.
Priya said:
1 decade ago
@senthil
Why should we consider 2001-2005? they have specified only 2006.
Why should we consider 2001-2005? they have specified only 2006.
Ayaan Chaudhary said:
6 years ago
I am unable to understand. This same question is in fitjee entrance exam.
Shashank said:
7 years ago
100 years = 76 ordinary years + 24 leap years (is it not 25 leap years).
Vidya sagar said:
9 years ago
Every last digit is known as odd no ie 29990 here "0" is know as odd.
Shweta said:
6 years ago
Thank you @Senthil. Very nice explanation. Now I understood properly.
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