Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 14 of 22.
Dipanjan said:
8 years ago
Anyone tell me,
What is the formula (0+0+6+1)?
I can't understand.
What is the formula (0+0+6+1)?
I can't understand.
Rajesh said:
8 years ago
Odd days in 1600 years = 0.
Odd days in 400 years = 0.
Why is it?
Odd days in 400 years = 0.
Why is it?
Neenu said:
8 years ago
Hi, I am not understanding the steps. Can anybody help me? please.
Thiru said:
1 decade ago
6/4 = 1.3.
take 1,
Now, 1+28+6+1.
36.
36/7.
1.
Which is sunday.
take 1,
Now, 1+28+6+1.
36.
36/7.
1.
Which is sunday.
Pratik said:
9 years ago
How can be taken as a feb as 28 day or 29 days please explain me?
Vignesh said:
9 years ago
How to understand the solution of this kind of calendar problem?
Ram said:
2 decades ago
How can I calculate that 5 yrs/ then whats meaning of odd days?
Manohar said:
2 decades ago
In i year how many weeks are there.
How is this odd day comes?
How is this odd day comes?
Ankita said:
1 decade ago
Why we have taken 1600 and 400 years only ? why not other year?
Tony said:
7 years ago
Why not we take no of odd days in 2000 is 0? Anyone explain me.
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