Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 15 of 22.
Ajay said:
1 decade ago
Why odd days for 1600 and 400 are zero? Thank you in advance.
Prasanth said:
8 years ago
Please explain clearly bro I don't understand this problem.
Ebrishman said:
9 years ago
How/why 100 years has 76 ordinary years and 24 leap years?
S.kowsalya said:
8 years ago
What was the day in 22 march, 1989? Can anyone solve this?
Anomie said:
6 years ago
@Anilkumar.
Odd days are the remainder, not the quotient.
Odd days are the remainder, not the quotient.
Revathi said:
1 decade ago
Pavithra your example is wrong. 2006-1900=106 its not 16.
Subin said:
1 decade ago
Why chosen 2001-2005 please explain as soon as possible ?
Harish said:
1 decade ago
Which year is exactly divided by 4 called as leap year?
Jhon said:
7 years ago
Why not adding 800 to 1600 and calculate it up to 2004?
Suresh said:
1 decade ago
Please explain why you consider 1600 is zero odd days?
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