Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 16 of 22.
Varun said:
1 decade ago
Is it @Rakhi's method is applicable for 17th june 1998
Babai said:
9 years ago
How does month codes make?
Please tell me, @Kannaiah.
Please tell me, @Kannaiah.
Janvi said:
1 decade ago
2011 year code will be 6. How can you explain this ?
Dinesh said:
1 decade ago
Can we apply dooms algorithm for all such problems?
Rushali said:
6 years ago
Why we are using 0+0+6+1 in it? Explain it briefly.
(1)
Jatin said:
1 decade ago
Why we have choose 1600 and 400 years separetely?
Ankita said:
1 decade ago
Why there is 1900 in above mentioned explanation?
Chinna said:
1 decade ago
Please explain me clearly. I am totally confused.
Jyothi said:
1 decade ago
@Deena.
How you got 2006-1900= 16 please explain.
How you got 2006-1900= 16 please explain.
Rabin said:
1 decade ago
Why there is 1900 in above mentioned explanation?
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