Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 17 of 22.
Raj sharma said:
5 years ago
Learn that every 400 years odd days will be zero.
Divya said:
5 years ago
I can't get this question. Please explain easily.
(1)
Snehal said:
1 decade ago
What is this odd day?
Can you explain it to me?
Can you explain it to me?
Moumita said:
9 years ago
Why we taken 0 as Sunday please help me any one?
PRIYA said:
9 years ago
If we put 1990 instead of 1900 it will be right.
Rahul said:
6 years ago
How the total odd days is found? please explain.
Narendra said:
5 years ago
How to take 400, 1600? Please anyone explain me.
Dev said:
1 decade ago
@Deena
How come 2006-1900=16 can you tell me ?
How come 2006-1900=16 can you tell me ?
Kamal said:
1 decade ago
2004 have also 0 why did you not use by 2004?
Naveen kumar said:
1 decade ago
Please explain one example with simple method?
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