Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 18 of 22.
Mohanravi Pinaprolu said:
5 years ago
How to find out the odd days? Please explain.
(3)
Praveena said:
1 decade ago
How it possible 2006-1900=16 do you explain.
Kaustubh said:
1 decade ago
How did 1600 and 400 come please explain me?
Priya said:
6 years ago
@Deena.
I think it is 1990 instead of 1900.
I think it is 1990 instead of 1900.
Ansari said:
1 decade ago
@arun i cant get it pls explain it brief...
Hemlatasharma said:
1 decade ago
What is the odd day please explain briefly.
Dipika said:
1 decade ago
@Deena
How you take 2006-1900=16? Its 106.
How you take 2006-1900=16? Its 106.
Kanakam said:
1 decade ago
How it possible 2006-1900=16 ........?
Suganthy said:
1 decade ago
Can we say that 1972 year has no odd days?
Ram Dafale @PRMIT said:
10 years ago
Use doomsday method to get faster result.
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