Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
215 comments Page 9 of 22.
Shefali said:
9 years ago
No. Of odd day in 1600 is 0.
No. Of odd days in 400 is 0.
This is hypothetical for this kind of questions remember this. For 2000 and after use 400, for 1900 and for example 1998 or 1976 etc use 300, for 1800 and after ex 1889, 1887 or any year starting with 18 use 200 instead of 400.
No. Of odd days in 400 is 0.
This is hypothetical for this kind of questions remember this. For 2000 and after use 400, for 1900 and for example 1998 or 1976 etc use 300, for 1800 and after ex 1889, 1887 or any year starting with 18 use 200 instead of 400.
Vignesh said:
9 years ago
How to understand the solution of this kind of calendar problem?
Praveen said:
9 years ago
Guys simply follow Deena's method. It is very simple and applicable for all kind of problems in calendars.
Kumar D said:
10 years ago
@Kannaiah.
Please explain how did you make the month code?
MONTH CODE.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
Why Jan is 1 and Feb is 4 and March is 4? Please explain the method of assuming the value.
Please explain how did you make the month code?
MONTH CODE.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
Why Jan is 1 and Feb is 4 and March is 4? Please explain the method of assuming the value.
Dalsukh said:
10 years ago
In simple calculation.
28/7 = 4.
The answer is four then remainder is 0. So it was Sunday.
28/7 = 4.
The answer is four then remainder is 0. So it was Sunday.
Kannaiah said:
10 years ago
MONTH CODE.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
YEAR CODE = 2006 - 6.
Sun = 1. Mon = 2. T = 3. W = 4. Thurs = 5.Fri = 6.Sat = 7 or 0.
28/5/2006.
D + M + Y + Leap year + Cc.
28 + 2 + 6 + 1 + 6 = 43.
43/7 = Q = 6, Re = 1.
SUNDAY = 1.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
YEAR CODE = 2006 - 6.
Sun = 1. Mon = 2. T = 3. W = 4. Thurs = 5.Fri = 6.Sat = 7 or 0.
28/5/2006.
D + M + Y + Leap year + Cc.
28 + 2 + 6 + 1 + 6 = 43.
43/7 = Q = 6, Re = 1.
SUNDAY = 1.
Ahmef said:
10 years ago
Hi @Deena.
Your explanation is the best method to solve the calendar problem.
Your explanation is the best method to solve the calendar problem.
Sajan said:
10 years ago
Hi, @Moumita.
It is in the series of:
0 => Sunday.
1 => Monday.
2 => Tuesday.
3 => Wednesday.
4 => Thursday.
5 => Friday.
6 => Saturday.
So, we taken 0 as Sunday.
It is in the series of:
0 => Sunday.
1 => Monday.
2 => Tuesday.
3 => Wednesday.
4 => Thursday.
5 => Friday.
6 => Saturday.
So, we taken 0 as Sunday.
Moumita said:
10 years ago
Why we taken 0 as Sunday please help me any one?
Pratik said:
10 years ago
How can be taken as a feb as 28 day or 29 days please explain me?
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