Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Thursday
Friday
Saturday
Sunday
Answer: Option
Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan.  Feb.   March    April    May 
(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Discussion:
215 comments Page 10 of 22.

Bharathi said:   10 years ago
Please help me guys. First how to find odd & even no in the month & year. Then say how to solve this kind of problems?

MANOJ said:   10 years ago
What's that thing that once a year twice a week for four months and a day is 6 times?

Vivek said:   10 years ago
Lets see that 2000 was a leap year so 1, 2, 3, 5 is non leap year and 2004 is leap year. So counting from 2001, to 5 there will be 6 odd day 1 for each non leap and 2 for 1 leap year next see in 2006 January has 31 day means 3 odd day (31/7), February has 0 (28/7), March has 3, April has 2, and for 28 in May 0 odd days.

So means total 8 days in 2006 means 1 week 1 day hence we total left of 1 odd day. From 2001 to 5 we have 6 odd and 1 in 2006 total 7. So 1 week again so starting day Sunday is answer.

Shubham said:   1 decade ago
By, doomsday method:

= Tuesday+(06/12)+rem(06/12)+rem(06/12)/4.

= Tuesday+0+0+0 means on 4th April Tuesday.

From 4th April to 28th may = 55 days = remain 6 odd days.

= Tuesday+6 = Sunday.

Ram Dafale @PRMIT said:   1 decade ago
Use doomsday method to get faster result.

Mounika said:   1 decade ago
Why the no. of odd days of 400 and 1600 are zero? Why not 2 they are leap years right?

Bhargavi said:   1 decade ago
Here is the reason for why 1600 and 400 are 0.

Counting of Odd Days:

1 ordinary year = 365 days = (52 weeks + 1 day. ).
1 ordinary year has 1 odd day.

1 leap year = 366 days = (52 weeks + 2 days).
1 leap year has 2 odd days.

100 years = 76 ordinary years + 24 leap years.

= (76 x 1 + 24 x 2) odd days = 124 odd days.
= (17 weeks + days) 5 odd days.

Number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) 3 odd days.

Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.

Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. Has 0 odd days.

Sumanth geras said:   1 decade ago
Jan=1.
Feb=4.
Mar=4.
Apr=0.
May=2.
Jun=5.
Jul=0.
Aug=3.
Sep=6.
Oct=1.
Nov=4.
Dec=6.

Days:

S=1.
M=2.
T=3.
W=4.
Th=5.
F=6.
Sat=7 or 0.

Day = Given date+Month no.+(x-1900)+(x-1900)/4.

X = The year we have to calculate.

**********************************************************************

Important notice for all who follow this formula.

First you should check whether the given year is a leap year or not.

If it is not a leap year our formula is perfect holds for every thing.

But if it is a leap year you should subtract 1 from the obtained answer otherwise you don't get correct answer.

Sonam Yangki said:   1 decade ago
Why do we take 1600 and 400? What is the relation of these two years particularly with the May?

Dinesh said:   1 decade ago
Can we apply dooms algorithm for all such problems?


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