Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 8 of 22.
Sathiyaraj said:
9 years ago
Assume, 01-01-01 be a Monday,
So, 2006/4 = 501 leap years + 2 days,
501/7 = 71 weeks + 4 days,
So, 31-12-2005 ends with Saturday (4 + 2 days = 6),
Hence, 01-01-2006 starts on Sunday,
Jan 31+ Feb 28 + Mar 31+ Apr 30 + May 28 = 148 days,
148/7 = 21 weeks + 1 days,
2005 ends on Saturday + 1 = Sunday,
So 28 May 2006 was Sunday.
So, 2006/4 = 501 leap years + 2 days,
501/7 = 71 weeks + 4 days,
So, 31-12-2005 ends with Saturday (4 + 2 days = 6),
Hence, 01-01-2006 starts on Sunday,
Jan 31+ Feb 28 + Mar 31+ Apr 30 + May 28 = 148 days,
148/7 = 21 weeks + 1 days,
2005 ends on Saturday + 1 = Sunday,
So 28 May 2006 was Sunday.
Kasiraja said:
9 years ago
The January month has 31days in 4weeks, per week 7days. 31/7 then the remaining is 3. Therefore 3 is considered as odd days. 4weeks * 7days = 28. The remaining 3 is odd days.
Vidya sagar said:
9 years ago
Every last digit is known as odd no ie 29990 here "0" is know as odd.
Babai said:
9 years ago
How does month codes make?
Please tell me, @Kannaiah.
Please tell me, @Kannaiah.
Babai said:
9 years ago
Doomsday method is easy to understand.
Ebrishman said:
9 years ago
How/why 100 years has 76 ordinary years and 24 leap years?
Kevin said:
9 years ago
Applying doomsday method is the best thing in this type of problems.
Doomsday for a year= (year/12) + Remainder (year/12) + rem (year/12/4) : (year is last two digits).
Last day of Feb = 4 april (4/4); 6 june (6/6); 8 aug (8/8); 10 oct (10/10).
ANCHOR = WEDNESDAY for 1900 - 1999.
ANCHOR = TUESDAY for 2000 - 2999.
Doomsday for a year= (year/12) + Remainder (year/12) + rem (year/12/4) : (year is last two digits).
Last day of Feb = 4 april (4/4); 6 june (6/6); 8 aug (8/8); 10 oct (10/10).
ANCHOR = WEDNESDAY for 1900 - 1999.
ANCHOR = TUESDAY for 2000 - 2999.
Ajay said:
9 years ago
@Deena. I can get yours with much ease.
Shubham singh said:
9 years ago
Dividing any number by 7 that gives you as a reminder which is know odd no.
Shefali said:
9 years ago
No. Of odd day in 1600 is 0.
No. Of odd days in 400 is 0.
This is hypothetical for this kind of questions remember this. For 2000 and after use 400, for 1900 and for example 1998 or 1976 etc use 300, for 1800 and after ex 1889, 1887 or any year starting with 18 use 200 instead of 400.
No. Of odd days in 400 is 0.
This is hypothetical for this kind of questions remember this. For 2000 and after use 400, for 1900 and for example 1998 or 1976 etc use 300, for 1800 and after ex 1889, 1887 or any year starting with 18 use 200 instead of 400.
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