Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 7 of 22.
Laila said:
1 decade ago
Keep year has 366 days so comparing to non keep year it has an extra day generally a non keep year has an odd day (non keep year has 365 days 364+1==365 so the last day is odd day) so keep year has 2 odd days.
Yog said:
1 decade ago
In 1 year there are 365days which year is non leap year.
365/7(to calculate number of weeks)
=52 is quotient and 1 is reminder(this is odd day)
This means for a non leap year there are 52 weeks and 1day.
365/7(to calculate number of weeks)
=52 is quotient and 1 is reminder(this is odd day)
This means for a non leap year there are 52 weeks and 1day.
Shubham said:
10 years ago
By, doomsday method:
= Tuesday+(06/12)+rem(06/12)+rem(06/12)/4.
= Tuesday+0+0+0 means on 4th April Tuesday.
From 4th April to 28th may = 55 days = remain 6 odd days.
= Tuesday+6 = Sunday.
= Tuesday+(06/12)+rem(06/12)+rem(06/12)/4.
= Tuesday+0+0+0 means on 4th April Tuesday.
From 4th April to 28th may = 55 days = remain 6 odd days.
= Tuesday+6 = Sunday.
Hem said:
9 years ago
I want to know how many independents like Mondays in this century same as the days?
Could you please tell me and as the same of Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday?
Could you please tell me and as the same of Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday?
Tina said:
1 decade ago
Hello @Thiru thanks for your explanation but could you please make it a bit clear so that we can understand better because from where you got the second calculation i.e 1+28+6+1 ?
Vishnupriya said:
1 decade ago
@Gopi.
A leap year is always divisible by 4(if it is not a century).
Eg: 2004, 1676.
And every fourth century is a leap year.
Eg: 400, 800, 1200.
But 1800 is not a leap year.
A leap year is always divisible by 4(if it is not a century).
Eg: 2004, 1676.
And every fourth century is a leap year.
Eg: 400, 800, 1200.
But 1800 is not a leap year.
Nitesh Nandwana said:
1 decade ago
@Ajay.
If you divide 1600 and 400 by 4 then reminder is nothing that's why odd days are zero. If reminder is 1 then odd day=1 and if reminder is 2 then odd days=2 is it ok ?.
If you divide 1600 and 400 by 4 then reminder is nothing that's why odd days are zero. If reminder is 1 then odd day=1 and if reminder is 2 then odd days=2 is it ok ?.
Kasiraja said:
9 years ago
The January month has 31days in 4weeks, per week 7days. 31/7 then the remaining is 3. Therefore 3 is considered as odd days. 4weeks * 7days = 28. The remaining 3 is odd days.
Ajay said:
1 decade ago
Deena's solution is correct just take 106 instead of 16 106/4 you will get quotient 26 and remainder 2 leave the remainder and take 26 you will get the right answer.
Sajan said:
9 years ago
Hi, @Moumita.
It is in the series of:
0 => Sunday.
1 => Monday.
2 => Tuesday.
3 => Wednesday.
4 => Thursday.
5 => Friday.
6 => Saturday.
So, we taken 0 as Sunday.
It is in the series of:
0 => Sunday.
1 => Monday.
2 => Tuesday.
3 => Wednesday.
4 => Thursday.
5 => Friday.
6 => Saturday.
So, we taken 0 as Sunday.
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