Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day)
1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 3 of 22.
ARNAB KAMILYA said:
2 months ago
0 + 2 + 6 + 1 = 9,
9/7 reminder is 2,
2 + 6 = 8.
8/7 reminder 1.
So, it is Sunday = answer.
9/7 reminder is 2,
2 + 6 = 8.
8/7 reminder 1.
So, it is Sunday = answer.
(1)
Meghana Mallela said:
3 weeks ago
So,we have to calculate the day that falls on 28th May 2006.
At first we have to find the odd days.
1)28
To find the odd days for 28 divide by 7
We get 0 odd days.
2)May
To find the odd days for may ,we should know the odd days of the months.
Jan- 31 days divide it by 7 we get the remainder 3 so, for Jan we have 3 odd days.
Similarly,
Feb-0 for ordinary years and 1 for leap years.
Mar-3
Apr-2
May-3
June-2
July-3
Aug-3
Sept-2
Oct-3
Nov-2
Dec-3
To find the odd days for may we add the odd days up to Apr.
Then 3+0(as 2006 is not a leap year)+3+2=8 divide it by 7 we get a remainder 1.
3) 2006
Take 2005, nearest leap century year is 2000+5 for 2000 0 odd days, and for 5 years there is a leap year.
1×2 = 2
4×1 = 4
Total = 6 odd days
Add all odd days.
0 + 1 + 6 = 7 ÷ 7 = 0.
Therefore the answer is SUNDAY.
At first we have to find the odd days.
1)28
To find the odd days for 28 divide by 7
We get 0 odd days.
2)May
To find the odd days for may ,we should know the odd days of the months.
Jan- 31 days divide it by 7 we get the remainder 3 so, for Jan we have 3 odd days.
Similarly,
Feb-0 for ordinary years and 1 for leap years.
Mar-3
Apr-2
May-3
June-2
July-3
Aug-3
Sept-2
Oct-3
Nov-2
Dec-3
To find the odd days for may we add the odd days up to Apr.
Then 3+0(as 2006 is not a leap year)+3+2=8 divide it by 7 we get a remainder 1.
3) 2006
Take 2005, nearest leap century year is 2000+5 for 2000 0 odd days, and for 5 years there is a leap year.
1×2 = 2
4×1 = 4
Total = 6 odd days
Add all odd days.
0 + 1 + 6 = 7 ÷ 7 = 0.
Therefore the answer is SUNDAY.
(1)
Eeshan said:
2 decades ago
I AM UNABLE TO GET THE SOLUTION OF THIS TYPE OF QUESTION. PLEASE HELP ME..
AND what do they mean by odd days.
please explain in a more better way if you can.
AND what do they mean by odd days.
please explain in a more better way if you can.
Thahseen said:
2 decades ago
What is meant by odd days?
Ram said:
2 decades ago
How can I calculate that 5 yrs/ then whats meaning of odd days?
Manohar said:
2 decades ago
In i year how many weeks are there.
How is this odd day comes?
How is this odd day comes?
Sindhu said:
1 decade ago
What are these odd days. I am unable to understand this problems? so if possible could you explain in a simple way.
Bhaskar said:
1 decade ago
How can u say 1600 years as 0 odd days?
Priya said:
1 decade ago
What does odd days mean?
Anilkumar said:
1 decade ago
@Priya suppose take the month of January, in this month you have 31 days right where 7 days in a week and 31/7 (3 will be quotient) 3 is nothing but odd days.
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