Aptitude - Calendar - Discussion

HERE AS IT IS GIVEN 28 MAY 2006.


28+ 1(CODE OF MAY) +06(LAST TWO DIGITS OF 2006)+06/4=(1),
SO 28+1+6+1 =36 then divide it by 7 for odd days,
36/7 = 1 is reminder.

So according to days
0 - SUNDAY
1 - MONDAY
2 - TUESDAY
3 - WEDNESDAY
4 - THURSDAY
5 - FRIDAY
6 - SATURDAY
7 - SUNDAY.

Here 1 is answer, So MONDAY (But) as 2006 is a leap year - 1 DAY SO (MONDAY - 1 = SUNDAY).

That's it. Thanks.

So,we have to calculate the day that falls on 28th May 2006.

At first we have to find the odd days.

1)28
To find the odd days for 28 divide by 7
We get 0 odd days.

2)May
To find the odd days for may ,we should know the odd days of the months.
Jan- 31 days divide it by 7 we get the remainder 3 so, for Jan we have 3 odd days.
Similarly,

Feb-0 for ordinary years and 1 for leap years.
Mar-3
Apr-2
May-3
June-2
July-3
Aug-3
Sept-2
Oct-3
Nov-2
Dec-3
To find the odd days for may we add the odd days up to Apr.
Then 3+0(as 2006 is not a leap year)+3+2=8 divide it by 7 we get a remainder 1.

3) 2006
Take 2005, nearest leap century year is 2000+5 for 2000 0 odd days, and for 5 years there is a leap year.
1×2 = 2
4×1 = 4
Total = 6 odd days
Add all odd days.
0 + 1 + 6 = 7 ÷ 7 = 0.
Therefore the answer is SUNDAY.

For all those who have confusion in this:

We calculate the years from 0 till 2005 so we split 2000 into 400 and 1600 and its odd day is 0, now left from 2000 to 2005 (5 yrs) = 4 ordinary years and 1 leap year = 4*1 + 2*1 = 6 the remainings.

I hope you all get it.

0 + 2 + 6 + 1 = 9,
9/7 reminder is 2,
2 + 6 = 8.
8/7 reminder 1.
So, it is Sunday = answer.

How to find out the odd days? Please explain.

Hello friends,

I think I have a better sollution. (I haven't read earlier sollutions, so if it is already here, then sorry and credit to the earlier post)

Remember this code for months
622503514624 (Jan, Feb, March,....Dec, for common years)
512503514624 (for leap years, jan code will be 5 and Feb code will be 1, that is the only difference in this code, It should be easy as we remember lots of mobile nos)

Then you'll have to remember years code.
for example 2011 year code will be 6
11+(leap years in 1st 11 years = 2)
so, 11+2 = 13/7, remains 6,the year code (for 2012, year code will be 1 (12+3= 15/7, remains 1)

Days code will be 0 for Sunday, 1 for Monday..like that!
For calculating day the formula is
Year code + month code + date
for example 18th October 2011
year code (6)+month code (6) + date (18)= 6+6+18 = 30/7..remains 2 means Tuesday

Do remember please, you'll be adding extra 0 for centuries divisible by 400 (say 2000), 5 for next century (2100), 3 for another next (2200) and 1 for just after that century (2300), and then 0 agian for 2400!

PS: I'm sorry but I'm not very good in explaining things. But this formula is doing wonders for me! Any help in this case..please contact me naveen.dhanerwal(at)gmail.com

Have a nice day!

What was the day of the week on 28th May, 2006?
Here is d ? right.

Okay,

Need to calculate 28th May, 2006 rite,
(Please refer important formulas first okay :))

Now 1600 years have 0 odd days because 1600/4= No reminder(we can divide 4 completely in 1600).

Now 400 years have 0 odd days because 400/4= No reminder(we can divide 4 completely in 400).

You confused here right.. okay see 1600+400=2000 so we came till 2000th year we need to calculate for 6 more years to reach 2006. Question is 2006 may right, so calculate till 2005 so 5 more years can calculate now okay then will calculate remaining days in 2006 okay.

So,

2001= its ordinary year so have 54 weeks and 1 odd day as per formula right
2002= its ordinary year so have 54 weeks and 1 odd day as per formula right.
2003= its ordinary year so have 54 weeks and 1 odd day as per formula right.
2004= 54 weeks and 2 odd day.
2005= its ordinary year so have 54 weeks and 1 odd day as per formula right.

1+1+1+2+1=6.
So total=6 odd days.

Now one more year which is 2006, here till 28th may needed so,

jan feb mar apr may
31 28 31 30 28th may ok.

31+28+31+30+28= 148 total days.

So calculate how many weeks and odd days in 148.

For this 148/7= 28 and reminder (1).
So 21 week and (1) odd day.

Add this(1) with (6) odd days that we calculate before of

So total 7 odd days now finish see.

1 2 3 4 5 6 7or(0)
Mo Tu We Th Fr Sat Sun

Total 7 odd days so 7th value OK... for example we got 5 odd days means answer will be Fri OK.

Here Sunday Enjoy :).

0 + 2 + 6 + 5 + 6 = 19/7 = 5 odd days which means Thursday.

In i year how many weeks are there.

How is this odd day comes?

What are these odd days. I am unable to understand this problems? so if possible could you explain in a simple way.