Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Monday
Tuesday
Wednesday
Thursday
Answer: Option
Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan.  Feb.   March    April    May      June 
(31 +  28  +  31   +   30   +   31   +   17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

Discussion:
165 comments Page 15 of 17.

Pratit said:   7 years ago
How many odd days in between 1901 to 2000? Please tell me the answer with the explanation.

Deepak padmule said:   7 years ago
In 1998.

i.e, 98 is a leap year so you should have to consider 29 days in Feb month but you hadn't considered it.

Bharathi said:   7 years ago
Can anybody derive and say 15th June 1998 is what day? Please

Shreya said:   7 years ago
How to calculate 1 odd day in 300years?

Roja st said:   7 years ago
Thanks @Sri Harsha.

Akshatha said:   7 years ago
Thanks for your answer @Sri Harsha.

Sreeja said:   7 years ago
Why should we take 1600 and 300 here? Please explain.

Suhel said:   7 years ago
@Rajesh.

Can you please explain how get the year code.

Akshakumar said:   6 years ago
1600 + 300 + 97 + (J to March)+17.

0 + 1 + {24(leap year)+73(ordinary y)}+(3+0+3+2+3) + 17.
1 + (24 * 2 + 73 * 1) + 17.
150/7.
21 week + 4 odd days.
Then the Ans is Thursday.

PRABHU said:   6 years ago
Take 1996 is a leap yera so it has 2 odd days.

Then 1997 has 1 odd day so total odd day till 1997 is;
(2+1)= 3.

Then,
Add the date till 01-01-1998 to 17- 06- 1997 so the total,
The day is 168 days divided it by 7, 168%7 = 0 odd days so total odd says from 1996 to 17-06-1998 is 3 only do that the day is WEDNESDAY.


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